4. The Coyote has an initial position vector of 
.
4a. The Coyote has an initial velocity vector of 
. His position at time 
is given by the vector
where 
is the Coyote's acceleration vector at time . He experiences acceleration only in the downward direction because of gravity, and in particular 
where 
. Splitting up the position vector into components, we have 
with
The Coyote hits the ground when 
:
4b. Here we evaluate 
at the time found in (4a).
5. The shell has initial position vector 
, and we're told that after some time the bullet (now separated from the shell) has a position of 
.
5a. The vertical component of the shell's position vector is
We find the shell hits the ground at
5b. The horizontal component of the bullet's position vector is
where 
is the muzzle velocity of the bullet. It traveled 3500 m in the time it took the shell to fall to the ground, so we can solve for :
~686newtons on earth and
~1617 newtons on jupiter
the formula is weight = gravitational acceleration * mass of the object
The net force acting on a box of mass 8.0kg that experiences an acceleration of 4.0m/s² is 32N. Details about net force can be found below.
<h3>How to calculate net force?</h3>
The net force of a body can be calculated by multiplying the mass of the body by its acceleration as follows:
Force = mass × acceleration
According to this question, a box with a mass of 8.0 kg is sitting on a frictionless surface and experiences an acceleration of 4.0 m/s2 to the right.
Net force = 8kg × 4m/s²
Net force = 32N
Therefore, the net force acting on a box of mass 8.0kg that experiences an acceleration of 4.0m/s² is 32N.
Learn more about net force at: brainly.com/question/18031889
#SPJ1
Air resistance force
tension force
spring force
frictional force
normal force
gravitational force
applied force
please give me brainly:)
Answer:
Decrease the distance between the two objects.
Explanation:
The force (F) of attraction between two masses (M₁ and M₂) separated by a distance (r) is given by:
F = GM₁M₂ / r²
NOTE: G is the gravitational force constant.
From the equation:
F = GM₁M₂ / r²
We can say that the force is directly proportional to the masses of the object and inversely proportional to the square of the distance between them. This implies that an increase in any of the masses will increase the force of attraction and likewise, a decrease in any of the masses will lead to a decrease in the force of attraction.
Also, an increase in the distance between the masses will result in a decrease in the force of attraction and a decrease in the distance between the masses, will result in an increase in the force of attraction.
Considering the question given above,
To increase the gravitational force between the two objects, we must decrease the distance between the two objects as explained above.
