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atroni [7]
3 years ago
11

Write an expression for the calculation the difference of the products of 5 and 2 and 5 and 1

Mathematics
1 answer:
kifflom [539]3 years ago
8 0
(5x2) - (5-1)
  10    -   4
        6
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1 2 4 and 5 please hurry
GREYUIT [131]

Answer:

1 is 0.6 and 2 is 612 3 is 39.2 and 4 is -3 and 5 is 9/4 or (2 1/4)

Step-by-step explanation:

:)

8 0
3 years ago
I really need help guys can some one plz help me it's for 10 points
11111nata11111 [884]

Answer:

\sqrt{8}----- 2units,2units

\sqrt{7} ------\sqrt{5}units,\sqrt{2}units

\sqrt{5}-------1unit,2units

3------2units, \sqrt{5}units

Step-by-step explanation:

Use pythagorean's theorem to solve each pair individually.

The instructions say that you have the two sides (a and b) and you have to match it with their hypothenuse.

Formula: c^2=a^2+b^2

1. a=\sqrt{5}, b=\sqrt{2}

Plug this into the formula.

c=\sqrt{(\sqrt{5} )^2+(\sqrt{2})^2 }

The square here eliminates the roots.

c=\sqrt{5+2}\\ c=\sqrt{7}

2. a=\sqrt{3}, b=4

c=\sqrt{(\sqrt{3} )^2+(4)^2}\\ c=\sqrt{3+16}\\ c=\sqrt{19}

3. a=2, b=\sqrt{5}

c=\sqrt{(2)^2+(\sqrt{5})^2 }\\ c=\sqrt{4+5}\\ c=\sqrt{9}\\ c=3

4. a=2, b=2

c=\sqrt{(2)^2+(2)^2}\\ c=\sqrt{4+4}\\ c=\sqrt{8}

5. a=1, b=2

c=\sqrt{(1)^2+(2)^2}\\ c=\sqrt{1+4}\\ c=\sqrt{5}

7 0
3 years ago
What percent of 30 is 33
Llana [10]
Hi!

To solve this we can set up a proportion and cross multiply.

\frac{33}{30}  \frac{x}{100}

33 x 100 = 3300
3300/30 = 110

The answer is 110%

Hope this helps! :)
3 0
3 years ago
An airplane is preparing to land at an airport. It is 53100 feet above the ground and is descending at the rate of 3300 feet per
Crank
9514 1404 393
Answer:
after 7 minutes
19,600 feet
Step-by-step explanation:
Here's the "pencil and paper" solution:
The two altitude equations are ...
y = 41300 -3100x
y = 2800x
They can be solved by setting the expressions for y equal to each other.
2800x = 41300 -3100x
5900x = 41300
x = 41300/5900 = 7
y = 2800·7 = 19600
The planes will both be at 19,600 feet after 7 minutes.
7 0
3 years ago
Why is there no tutor​
pickupchik [31]
I think you have to follow someone and ask them to be your tutor.
4 0
3 years ago
Read 2 more answers
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