Write an expression for the calculation the difference of the products of 5 and 2 and 5 and 1

Mathematics

1 answer:

kifflom [539]2 years ago

8 0

(5x2) - (5-1)
10 - 4
6

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Helppppp mereeeeeeeeeee

Vera_Pavlovna [14]

Answer:

A. (x-5)(x-7)

B. It means the zeroes of the graph are at (5,0) and (7,0)

Step-by-step explanation:

find what + what equals -12, and multiples to 35.

List all multiples of 35.

1 35

5 7

- 12 is negative so that means it is -5 and -7

(x-5)(x-7)

The factor numbers are where the zeroes on a graph are, but whatever is in parenthesis, the number is opposite on a graph (e.g. if it was (x-3), the zero would be (3,0)

4 0

3 years ago

Use zero property to solve the equation. F(x)=3x(x+7)-2(x+7)

oksian1 [2.3K]

Answer:

x = -7 or x = 2/3

Step-by-step explanation:

I'm assuming you meant solve for x when f(x) = 0.

f(x) = 3x(x + 7) - 2(x + 7)

0 = (x + 7)(3x - 2) -- Both terms have a common factor of (x + 7) so we can group them

x + 7 = 0 or 3x - 2 = 0 -- Use ZPP

x = -7 or x = 2/3 -- Solve

7 0

2 years ago

A pharmaceutical company receives large shipments of aspirin tablets. The acceptance sampling plan is to randomly select and tes

hammer [34]

Answer:

a) The probability that this whole shipment will be accepted is 30%.

b) Many of the shipments with this rate of defective aspirin tablets will be rejected.

Step-by-step explanation:

We have a shipment of 3000 aspirin tablets, with a 5% rate of defects.

We select a sample of size 48 and test for defectives.

If more than one aspirin is defective, the batch is rejected.

The amount of defective aspirin tablets X can be modeled as a binomial distribution random variable, with p=0.55 and n=48

We have to calculate the probabilities that X is equal or less than 1: P(X≤1).

$P(X\leq1)=P(X=0)+P(X=1)\\\\\\P(0)=\binom{48}{0}(0.05)^0(0.95)^{48}=1*1*0.0853=0.0853\\\\\\P(1)=\binom{48}{1}(0.05)^1(0.95)^{47}=48*0.05*0.0897=0.2154\\\\\\P(X\eq1)=0.0853+0.2154=0.3007$