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dolphi86 [110]
4 years ago
12

How to find the midpoint formula

Mathematics
1 answer:
defon4 years ago
8 0
\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ 6}}\quad ,&{{ -1}})\quad 
%  (c,d)
&({{ -3}}\quad ,&{{ -13}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left(\cfrac{-3+6}{2}~,~\cfrac{-13-1}{2}  \right)

and fairly sure you know how much that is.
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AlexFokin [52]

Answer:

7

Step-by-step explanation:

8 0
3 years ago
Erica filled 2/5 of a page of her notebook on Monday. She filled 5/6 of a page on Tuesday. How many pages did Erica fill in her
SOVA2 [1]
2/5 + 5/6 

Start with the denominator 

To compare or combined they must be the same kind. Basically the bottom numbers have to be the same.


5 x 6 = 30 

Now go across  from the bottom number to the top 


5 x 5 = 25
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8 0
4 years ago
At the market, 5 light bulbs cost $9. How much do 7 light bulbs cost?
Rudiy27
Hello!

To solve this, find the cost of a single light bulb first, by dividing 9 / 5.

9 / 5 ==> 1.80

One light bulb is $1.80

Now, multiply 1.80 by 7.

1.80 * 7 = 12.6

7 light bulbs cost $12.6

Hope this helps! ☺♥


6 0
4 years ago
Read 2 more answers
What is the value of the interquartile range of the data below? A box-and-whisker plot. The number line goes from 0 to 52. The w
Softa [21]

Answer:

The interquartile range is 12.

Step-by-step explanation:

In a box-and-whisker plot, the left edge of the box is the lower quartile and the right edge of the box is the upper quartile. The line dividing the box is the median. The end of the left whisker shows the minimum value. The end of the right whisker shows the maximum value.

In your question, the lower quartile is 29, the upper quartile is 41, while the median is 32. The minimum value is 10 and the maximum value is 51.

The formula for the interquartile range is as follows:

Interquartile Range = Upper quartile - Lower quartile

In this question, interquartile range = 41 - 29 which equals 12. Hence, the answer is 12.  

5 0
3 years ago
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the length of a rectangle is 5 centimeters less than its width. what are the dimensions of the rectangle if it’s area is 176 squ
Allushta [10]

11 is the length

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3 0
3 years ago
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