Answer:
Explanation:
We have given that the battery has an internal emf of 9 volt
So E = 9 volt
Capacitance
It is given that on the terminal voltage is only 80% of potential difference
So V = 0.8×9 = 7.2 volt
We know that energy stored in the capacitor is given by
The molarity remains the same so the ratio does not change
This is an example of state change from solid to liquid.
Answer: a) 6.7 ; b) -9.5 * 10^-7 C induced in the dielectric on the positive plate and 9.5 * 10^-7 C induced in the other side of the dielectric close to the negative plate.
Explanation: In order to solve this problem we have to use the formule for two parallel plates capacitor, which is given by:
C= εo*A/d where A and d are the cross section and separation of the plates, respectively.
Aditionally we know that C= Q/ΔV and ΔV = E*d
By uning both expression we have:
C= εo*A/d=Q/ΔV=εo*A/d=Q/E*d then
with a dielectric between the plates, the new C is obtained by multiply by k the initial capacitance.
finally we have
εo*k*A=Q/E
then k= Q/(E*εo*A)= 6.7
In the dielectric is induced oposite charge to each plate of the capacitor, The value of induced charge in the dielectric is the same for the capacitor but with oposite sign.