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ozzi
4 years ago
13

SOMEONE PLEASE HELP I DON'T GET THIS!!

Mathematics
1 answer:
Semenov [28]4 years ago
7 0

HI umm.. I can see the thing that you need help with sorry not trying to be rude but what do you need help with?

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What is the best answer to this question
Bas_tet [7]

The radius is 3.75 feet.

5 0
4 years ago
A box of peanut butter crackers contains 12 individual snacks s is equal to 12 times the number of boxes of crackers b. What is
Luda [366]

Answer:

B+12=12 i am learning this this week

Step-by-step explanation:

6 0
4 years ago
Find the 57th term of the sequence 74n-29, where n represents the position of a term in sequence.
zhannawk [14.2K]

Answer:

4189

Step-by-step explanation:

Given sequence is:

a_n=74n-29

Plugging n = 57 in the given sequence, we find:

a_{57}=74(57)-29

a_{57}=4218-29

\huge \red{a_{57}= \boxed{4189}}

5 0
3 years ago
Two water pumps are filling a pool. One of the pumps is high power and can fill the pool 5 hours before the other can do. Howeve
9966 [12]

L = hours for the slower pump to fill the pool

L - 5 = hours for the high power pump, since it can do it in 5 hours less.

since the slower pump takes L hours, the faster pump takes then L - 5 hours.

we know both pumps together take 3 hours to do <u>half of the pool</u>, so that means that to fill up <u>the whole pool it takes them 6 hours</u>.

since the slower pump can do it alone in L hours, in 1 hour it has done 1/L of the whole thing.

likewise, since the faster pump can do it in L-5 hours, in 1 hour alone it has done 1/(L-5) of the whole job.


\bf \stackrel{\textit{slower pump's rate}}{\cfrac{1}{L}}~~~~+\stackrel{\textit{faster pump's rate}}{\cfrac{1}{L-5}}~~~~=~~~~\stackrel{\textit{total done in 1 hour}}{\cfrac{1}{6}} \\\\\\ \textit{let's multiply both sides by }\stackrel{LCD}{6(L)(L-5)}\textit{ to do away with the denominators} \\\\\\ 6(L)(L-5)\left( \cfrac{1}{L}+\cfrac{1}{L-5} \right)=6(L)(L-5)\left( \cfrac{1}{6} \right)


\bf 6(L-5)+6L=(L)(L-5)\implies 6L-30+6L \\\\\\ 12L-30=L^2-5L\implies 0=L^2-17L+30 \\\\\\ 0=(L-15)(L-2)\implies L= \begin{cases} \boxed{15}\\ 2 \end{cases}


now, we can't use L = 2, because, the whole job by both is done in 6 hours, there's no way the slower pump can do it in less than that, so L = 15.

now if L = 15, then L - 5 = 10.

5 0
4 years ago
How to plot six over four on number line
Gnoma [55]
Im pretty sure you would go six over and four up

Hope I helped 
good luck!!!!
4 0
4 years ago
Read 2 more answers
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