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V125BC [204]
3 years ago
12

Atomic mass - Atomic Number = protons electrons Average Mass neutrons

Chemistry
1 answer:
kiruha [24]3 years ago
6 0

Answer: neutrons

Explanation:

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List science of kinesiology that interest you? Why there science interest you
Mkey [24]

Answer:

The study of the human body as a machine for the performance of work has its foundations in three major areas of study—namely, mechanics, anatomy, and physiology; more specifically, biomechanics, musculoskeletal anatomy, and neuromuscular physiology. Explanation:

5 0
3 years ago
In the reaction BaCO3 + 2HNO3 + Ba(NO3)2 + CO2 + H2O, what mass of Ba(NO3)2 can be formed by combining 55 g BaCO3 and 26 g HNO3
Nataliya [291]

From the stoichiometry of the reaction, the mass of barium nitrate produced is 54.9 g.

<h3>Stoichiometry</h3>

The term stoichiometry refers to mass - volume relationships. Stoichiometry can be used to calculate the amount, mass or volume of reactants and products from the balanced reaction equation.

The equation of the reaction is written as follows;

BaCO3 + 2HNO3 ------>  Ba(NO3)2 + CO2 + H2O

Number of moles of BaCO3  = 55 g/197.34 g/mol = 0.28 moles

Number of moles of HNO3 = 26 g/63.01 g/mol = 0.41 moles

From the reaction equation;

1 mole of BaCO3 reacts with 2 moles of HNO3

0.28 moles of BaCO3 reacts with 0.28 moles ×  2 moles/1 mole = 0.56 moles

There is not enough HNO3 hence it is the limiting reactant.

Number of moles of Ba(NO3)2 produced  is obtained from;

2 moles of HNO3  yields 1 mole of Ba(NO3)2

0.41 moles of HNO3  yields 0.41 moles × 1 mole/2 moles

= 0.21 moles of Ba(NO3)2

Mass of  Ba(NO3)2  = 0.21 moles  × 261.337 g/mol = 54.9 g

Learn more about stoichiometry: brainly.com/question/9743981

8 0
3 years ago
Please answer this question
lukranit [14]
I think it will be B. Hope it helps :)
6 0
3 years ago
A student dissolves of 15 g aniline in of a solvent with a density of . The student notices that the volume of the solvent does
VikaD [51]

The given question is incomplete. The complete question is ;

A student dissolves of 15 g aniline in 200 ml of a solvent with a density of 1.05 g/ml. The student notices that the volume of the solvent does not change when the aniline dissolves in it. Calculate the molarity and molality of the student's solution. Be sure each of your answer entries has the correct number of significant digits.

Answer: The molarity is 0.81 M and molality is 0.82 m

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute  

V_s = volume of solution in ml = 200 ml

{\text {moles of solute}=\frac{\text {given mass}}{\text {molar mass}}=\frac{15g}{93g/mol}=0.16mol

Now put all the given values in the formula of molarity, we get

Molarity=\frac{0.16\times 1000}{200}=0.81M

Thus molarity is 0.81 M

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

Molarity=\frac{n\times 1000}{W_s}

where,

n = moles of solute

W_s = weight of solvent in g

{\text {moles of solute}=\frac{\text {given mass}}{\text {molar mass}}=\frac{15g}{93g/mol}=0.16mol

Mass of solution = Density\times Volume=1.05g/ml\times 200ml=210g

mass of solvent = mass of solution - mass of solute = (210 - 15) g = 195 g

Now put all the given values in the formula of molality, we get

Molality=\frac{0.16\times 1000}{195g}=0.82mole/kg

Therefore, the molality of solution is 0.82m

3 0
3 years ago
Consider the following isomerization reactions of some simple sugars and values for their standard Gibbs free energy ΔGo:reactio
koban [17]

Answer:

Explanation:

glucose-1-phosphate  →  glucose-6-phosphate,  ΔGo = -7.28 kJ/mol

fructose-6-phosphate → glucose-6-phosphate,    ΔGo = -1.67 kJ/mol

subtracting the equation

glucose-1-phosphate - fructose-6-phosphate  = 0 , ΔGo =  -7.28  - ( -1.67 ) kJ / mol

glucose-1-phosphate  = fructose-6-phosphate      ΔGo  = - 5.61 kJ / mol

- ΔGo = RT lnK

5.61 x 10³ = 8.31 x 298 x lnK

lnK = 2.265

K = 9.63 .

3 0
3 years ago
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