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LUCKY_DIMON [66]
3 years ago
5

What sex is the person who has the karyotype described in Steps 3-4? How do you know?

Chemistry
1 answer:
NISA [10]3 years ago
8 0
XY is a male, and XX is a female.
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On average, Earth’s crust contains about 8.1% aluminum by mass. If a standard 12-ounce soft drink can contains approximately 15
MrMuchimi

Answer:

5400 cans

Explanation:

First we convert the total weight, 1 ton, to grams:

1ton=1x10^{6}g

Now we need to know the mass of aluminum:

m_{Al}=\frac{10^{6}*8.1}{100} =81000g

Now we make the relation between the mass of aluminum in 1 ton of the earth's crust and the mass of aluminum per can:

n=\frac{81000g}{15g/can} =5400cans

8 0
3 years ago
How manymoles of each ion are present in 175 mL of 0.147 M Fe2(SO4)3?
lilavasa [31]

Answer: 0.0257 moles of Fe^{3+}  and 0.0257 moles of SO_4^{2-}

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{moles}{\text {Volume in L}}

moles of  Fe_2(SO_4)_3=Molarity\times {\text {Volume in L}}=0.147\times 0.175L=0.0257moles

The balanced reaction for dissociation will be:

Fe_2(SO_4)_3\rightarrow Fe^{3+}+SO_4^{2-}

According to stoichiometry:  

1 mole of Fe_2(SO_4)_3 gives 1 mole of Fe^{3+}  and 1 mole of SO_4^{2-}

Thus there will be 0.0257 moles of Fe^{3+}  and 0.0257 moles of SO_4^{2-}

8 0
3 years ago
The layering of eroded sediments is called:
Aleks [24]
4. the rock cycle is the layering of eroded sediments 
6 0
3 years ago
What is the boiling point of a 1.5 m aqueous solution of fructose? the boiling point elevation constant of water is 0.515°c/m.
GREYUIT [131]
Answer is: <span>he boiling point of a 1.5 m aqueous solution of fructose is </span>100.7725°C.
The boiling point elevation is directly proportional to the molality of the solution according to the equation: ΔTb = Kb · b.<span>
ΔTb -  the boiling point elevation.
Kb - the ebullioscopic constant. of water.
b - molality of the solution.
Kb = 0.515</span>°C/m.
b = 1.5 m.
ΔTb = 0.515°C/m · 1.5 m.
ΔTb = 0.7725°C.
Tb(solution) = Tb(water) + ΔTb.
 Tb(solution) = 100°C + 0.7725°C = 100.7725°C.
5 0
3 years ago
The British gold sovereign coin is an alloy of gold and copper having a total mass of 7.988 g, and is 22-karat gold.
azamat

Answer:

(a) m_{gold}=7.322g

(b)

V_{gold}=0.379cm^3

V_{copper}=0.122cm^3

(c) \rho _{coin}=15.94g/cm^3

Explanation:

Hello,

(a) In this case, with the given formula we easily compute the mass of gold contained in the sovereign  as shown below:

m_{gold}=\frac{m_{tota}*karats}{24}=\frac{7.988g*22}{24}=7.322g

(b) Now, by knowing the density of gold and copper, 19.32 and 8.94 g/cm³ respectively, we compute each volume, by also knowing that the rest of the coin contains copper:

V_{gold}=\frac{m_{gold}}{\rho_{gold}} =\frac{7.322g}{19.32g/cm^3}=0.379cm^3

m_{copper}=7.988g-7.322g=1.09g\\V_{copper}=\frac{m_{copper}}{\rho_{copper}}=\frac{1.09g}{8.94g/cm^3}  \\\\V_{copper}=0.122cm^3

(c) Finally, the volume is computed by dividing the total mass over the total volume containing both gold and copper:

\rho _{coin}=\frac{m_{total}}{V_{gold}+V_{copper}}=\frac{7.988 g}{0.379cm^3+0.122cm^3}\\  \\\rho _{coin}=15.94g/cm^3

Best regards.

3 0
3 years ago
Read 2 more answers
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