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Eva8 [605]
4 years ago
9

Arrange the elements given below in the increasing order of their atomic size. Element A 1s22s22p6 
Element B 1s22s2
 Element C

1s22s22p63s1
 Element D 1s22s22p3
Chemistry
1 answer:
Georgia [21]4 years ago
3 0

Answer:

The answer to your question is: B, D, A, C

Explanation:

Atomic size is the distance from the nucleus to the outermost shell or valence shell. Then, we can know the atomic size for the number of electrons in an element.

In this exercise, there are 4 elements and their number of electrons, so we must know this number for each element.

Element A 1s22s22p6          has 8 electrons

Element B 1s22s2                 has 4 electrons

Element C 1s22s22p63s1    has 11 electrons

Element D 1s22s22p3             has 7 electrons

The smallest atomic size is for Element B, then Element D, Element A and the biggest atomic size is for element C.

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In the reaction _Al 3O2→2Al2O3, what coefficient should be placed in front of the Al to balance the reaction? 1 2 3 4.
luda_lava [24]

Answer:

D.) 4

Explanation:

Al + 3 O₂ --> 2 Al₂O₃

In the equation, there are:

<em>Reactants:</em> 1 Al and 6 O

<em>Products:</em> 4 Al and 6 O

To determine how many atoms there are of each, you multiply the coefficients by the subscripts attached to the atoms. While the question doesn't ask, as you can see, the oxygen atoms are balanced because there is an equal amount on both sides. To balance the aluminum atoms, you can get 4 aluminum atoms on the reactants side by using a coefficient of 4.

The new equation would look this this:

4 Al + 3 O₂ --> 2 Al₂O₃

There are now:

<em>Reactants:</em> 4 Al and 6 O

<em>Products:</em> 4 Al and 6 O

4 0
2 years ago
Magnesium reacts with the oxygen in the air to form magnesium oxide. If 35 g of O2 was used in the reaction. How many Liters of
Sedbober [7]

Answer:

20.02 Liters

Explanation:

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The relationship between the quantities is given as;

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n = mass / Molar mass = 35 / 32 = 1.09375 mol

V = nRT / P

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6 0
3 years ago
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4 years ago
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Calculate the volume of 0.684mol of carbon dioxide at s.t.p. show working
solong [7]

Answer: The volume of 0.684 mol of carbon dioxide at s.t.p. is 15.3 L

Explanation:

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R = gas constant = 0.0821Latm/Kmol

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6 0
3 years ago
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