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Eva8 [605]
3 years ago
9

Arrange the elements given below in the increasing order of their atomic size. Element A 1s22s22p6 
Element B 1s22s2
 Element C

1s22s22p63s1
 Element D 1s22s22p3
Chemistry
1 answer:
Georgia [21]3 years ago
3 0

Answer:

The answer to your question is: B, D, A, C

Explanation:

Atomic size is the distance from the nucleus to the outermost shell or valence shell. Then, we can know the atomic size for the number of electrons in an element.

In this exercise, there are 4 elements and their number of electrons, so we must know this number for each element.

Element A 1s22s22p6          has 8 electrons

Element B 1s22s2                 has 4 electrons

Element C 1s22s22p63s1    has 11 electrons

Element D 1s22s22p3             has 7 electrons

The smallest atomic size is for Element B, then Element D, Element A and the biggest atomic size is for element C.

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For the following reaction, 7.53 grams of benzene (C6H6) are allowed to react with 8.33 grams of oxygen gas. benzene (C6H6) (l)
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Answer:

The maximum amount of CO2 that can be formed is 9.15 grams CO2

O2 is the limiting reactant

There will remain 4.82 grams of benzene

Explanation:

Step 1: Data given

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Mass of oxygen gas = 8.33 grams

Molar mass of benzene = 78.11 g/mol

Molar mass oxygen gas = 32.00 g/mol

Step 2: The balanced equation

2C6H6 + 15O2 → 12CO2 + 6H2O

Step 3: Calculate moles

Moles = mass / molar mass

Moles C6H6 = 7.53 grams / 78.11 g/mol

Moles C6H6 = 0.0964 moles

Moles O2 = 8.33 grams / 32.00 g/mol

Moles O2 = 0.2603 moles

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For 2 moles benzene we need 15 moles O2 to produce 12 moles CO2 and 6 moles H2O

O2 is the limiting reactant. It will completely be consumed ( 0.2603 moles). Benzene is in excess. there will react 2/15 * 0.2603 = 0.0347 moles

There will remain 0.0964 - 0.0347 = 0.0617 moles benzene

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For 2 moles benzene we need 15 moles O2 to produce 12 moles CO2 and 6 moles H2O

For 0.2603 moles O2 we'll have 12/15 * 0.2603 = 0.208 moles CO2

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