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garri49 [273]
3 years ago
8

Can some tell me plz

Chemistry
2 answers:
valentina_108 [34]3 years ago
5 0

Answer: stay the same because it's a solid.

Explanation:

Yuki888 [10]3 years ago
3 0

Answer:

a) Stay the same

Explanation:

If you were to bring a basketball to a basketball court, the ball's mass wouldn't change.

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Granite is stronger, and it doesn't grow mold in the rain. It also looks better than marble and is easier to carve. 
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Read 2 more answers
1) A mixture of anhydrous sodium carbonate and sodium hydrogencarbonate of mass 10.000 g was heated until it reached a constant
vodomira [7]

The masses of the components are obtained as;

  • Sodium hydrogen carbonate = 3.51 g
  • Sodium carbonate =  8.708 g
<h3>What is decomposition?</h3>

The term decomposition has to do with the breakdown of the given substance into its components. The components of sodium hydrogen carbonate could be identified as water vapor, carbon dioxide gas and sodium carbonate. Among these products that have been listed here, we can see that it is only the sodium carbonate that remains as a solid. The others are gases that move away from the system that is under study.

Now putting down the equation of the reaction, we have;

2NaHCO_{3} (s) ----- > Na_{2} CO_{3} (s) + CO_{2} (g) + H_{2} O(g)

Now, the loss in  mass must be due to the carbon dioxide and the water. Hence we obtain the loss in mass to be 10.000 g -  8.708 g = 1.292 g

Mass of sodium hydrogen carbonate = 2 * 88 g/mol * 1.292 g/62 g/mol

= 3.51 g

Learn more about anhydrous sodium carbonate :brainly.com/question/20479996

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1 year ago
Differentiate between nuclear charge and effective nuclear charge​
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3 years ago
5 properties of acids
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Answer:

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Explanation:

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2 years ago
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Given the two reactions PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq), K3 = 1.89×10−10, and AgCl(aq)⇌Ag+(aq)+Cl−(aq), K4 = 1.25×10−4, what is the
Sergio [31]

Answer:

1.2\times 10^{-2}

Explanation:

The given reactions are:

PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq)     K_3 = 1.89\times 10^{-10}

AgCl(aq)⇌Ag+(aq)+Cl−(aq)           K_4 = 1.25\times 10^{-4}

Required reaction is:

PbCl2(aq)+2Ag+(aq)⇌2AgCl(aq)+Pb2+(aq)

K_f = \frac{K_3}{K_4^2}\\=\frac{1.89\times 10^{-10}}{1.25\times 10^{-4}}^2\\=1.2\times 10^{-2}

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3 years ago
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