I need help with someone explaining how to find the range of this! This course didn’t explain anything!

Mathematics

1 answer:

zaharov [31]2 years ago

4 0

Answer:

$(-infinity,3)$ , D

Step-by-step explanation:

3 if x is greater than or equal to 1 is nothing. That leaves us with $h(x)=2x+1$ if x<1. If you substitute in 1 for x, you get 3, but of course that isn't possible, so the range is $(-infinity,3)$ , which is D.

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A theater has a discount pass that cost nine dollars with the past admission is $6.50 per movie. mike tyrell and juanita all bou

tia_tia [17]

Answer:

They saw <u>24</u> movies.

Step-by-step explanation:

The question is incomplete so the complete question is below:

A theater has a discount pass that cost nine dollars with the pass, admission is $6.50 per movie. Mike, Tyrell and Juanita all bought a pass and went to see movies together they spent a total of $183. Write and solve an equation to find out how many movies they saw.

Now, to find the number of movies they saw.

Let the number of movies they saw be $x.$

Discount pass = $9.

With the pass admission per movie is $6.50.

Total number of people = 3.

Total money spent = $183.

So, to get the number of movies they saw we write an equation:

$3(9)+6.50(x)=183$

Now, to solve the equation:

$3(9)+6.50(x)=183$

$27+6.50x=183$

<em>Subtracting on both sides by 27 we get:</em>

$6.50x=156$

<em>Dividing both sides by 6.50 we get:</em>

$x=24.$

Therefore, they saw 24 movies.

4 0

3 years ago

an ordered pair where the x and y coordinate are the same lies in the 1st or 3rd quadrant. true, sometimes true or not true?. ex

Zarrin [17]

The quadrants are as follows:

The 1st quadrant has the points which have both x and y positive and the 3rd quadrant has the points which have both x and y negative. If the ordered pair and the same x and y value, if ons is positive, the other also is, and the same for negative.

So, at first we see that there are point where the x and y are the same and that are in the 1st or 3rd quadrant.

However, there is one special case:

When x and y are 0, that is, the ordered pair is (0, 0).

Since this point is the origin, it doesn't lie on any of the quadrants.

Thus, this affirmative is sometimes true. Every point but (0, 0) that have same x and y values are in the 1st or 3rd quadrant except for (0, 0).