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3 years ago

I need help with someone explaining how to find the range of this! This course didn’t explain anything!

Mathematics

1 answer:

zaharov [31]3 years ago

4 0

Answer:

$(-infinity,3)$ , D

Step-by-step explanation:

3 if x is greater than or equal to 1 is nothing. That leaves us with $h(x)=2x+1$ if x<1. If you substitute in 1 for x, you get 3, but of course that isn't possible, so the range is $(-infinity,3)$ , which is D.

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Please help, im having a lot of difficulty with this problem and i cant seem to figure it out,

FrozenT [24]

Answer:

12/13

Step-by-step explanation:

Use SOH-CAH-TOA.

Sine = Opposite / Hypotenuse

Cosine = Adjacent / Hypotenuse

Tangent = Opposite / Adjacent

sin B = opposite / hypotenuse

The side opposite of angle B is side b. The hypotenuse is c.

sin B = b / c

sin B = 12 / 13

3 0

3 years ago

Dan earns £8.30 per hour how much will he earn for 9 hours work

Nana76 [90]

Hey there!

$\large\boxed{\$74.70}$

The unit rate is 8.30 for every hour.

If he earns $8.30 an hour and works 9 hours, multiply 8.30 by 9.

8.30 x 9 = 74.70

Hope this helps!

3 0

3 years ago

Read 2 more answers

In a right triangle the leg opposite to the acute angle of 30° is 7 in. Find the hypotenuse and other leg.

Maksim231197 [3]

This is a 30-60-90 triangle.
Therefore,
7 is A
the other leg is A√3
And the hypotenuse is 2A
So the other leg is 7√3 and the hypotenuse is 14

5 0

3 years ago

Read 2 more answers

Which expression is equivalent to 2x2 + (4x - 6x2) + 9 - (6x + 3)?

Troyanec [42]

Answer:

-4 $x^2$ -10x+6

Step-by-step explanation:

I am going to assume the (Something)x2 means (Something) $x^2$ . Then, the expression is 2 $x^2$ -6 $x^2\\$ +4x-6x+9-3=-4 $x^2$ -10x+6

4 0

3 years ago

Read 2 more answers

Make r the subject of the formula <br><img src="https://tex.z-dn.net/?f=v%20%3D%20%5Cpi%20%5C%3A%20h%20%7B%7D%5E%7B2%7D%28r%20-%

Vaselesa [24]

Answer:

$\boxed{r = \frac{h}{3} + \frac{v}{\pi {h}^{2} } }$

Step-by-step explanation:

$Solve \: for \: r: \\ = > v= \pi {h}^{2}(r - \frac{h}{3} ) \\ \\ v=\pi {h}^{2}(r - \frac{h}{3} )is \: equivalent \: to \: {h}^{2}\pi(r - \frac{h}{3} ) = v: \\ = > {h}^{2}\pi(r - \frac{h}{3} ) = v \\ \\ Divide \: both \: sides \: by \: \pi {h}^{2} : \\ = > r - \frac{h}{3} = \frac{v}{\pi {h}^{2} } \\ \\ Add \: \frac{h}{3} \: to \: both \: sides: \\ = > r = \frac{h}{3} + \frac{v}{\pi {h}^{2} }$

8 0

3 years ago