Answer:
10 inches
Step-by-step explanation:
Area is qual to length times width.
A = lw
Rearrange this to find width.
w = A/l
Now plug in your known numbers and simplify.
w = 40/4
w = 10
Answer:
382.925 feets
Step-by-step explanation:
The solution diagram is attached below :
Converting radian measurement to degree :
radian angle * 180/π = degree angle
1.2 * 180/π = 68.755°
0.9 * 180/π = 51.566°
Height of dam is h:
Using trigonometry :
Tan θ = opposite / Adjacent
Tan 68.755° = h / x
h = x Tan 68.755° - - - (1)
Tan 51.566° = h / (155+x)
h = (155+x) tan 51.566° - - - (2)
Equate (1) and (2)
x Tan 68.755 = (155+x) Tan 51.566
x Tan 68.755 = 155tan 51.566 + x tan 51.566
x Tan 68.755 = 195.32311 + x Tan 51.566
x Tan 68.755 - x Tan 51.566 = 195.32311
x(tan 68.755 - tan 51.566) = 195.32311
x * 1.3120110 = 195.32311
1.3120110x = 195.32311
x = 195.32311 / 1.3120110
x = 148.87307
Using :
h = x Tan 68.755
h = 148.87307 * tan(68.755)
h = 382.92539
h = 382.925 feets
Answer:
Part 1) The volume of each beam is 
Part 2) You can fill 
Part 3) Yes, the amount of sand left over is 
Step-by-step explanation:
Part 1) What is the total volume of each beam?
The volume of a cylinder is equal to

we have

----> the radius is half the diameter
assume

substitute the values


Part 2) How many beams can you fill with this sand?
we know that
You are given a container with a 50,000 sq ft of sand for your beams
<em>Note</em> Is a 50,000 cubic foot of sand instead of 50,000 sq ft of sand
Divide the total volume of sand by the volume of each beam to obtain the number of beams

Round down

Part 3) Will you have any sand left over? If so how much?
yes

2x+y-3z=12
2x=4z-y
x=2z-y/2
Answer:
The sample standard deviation is 393.99
Step-by-step explanation:
The standard deviation of a sample can be calculated using the following formula:
![s=\sqrt[ ]{\frac{1}{N-1} \sum_{i=1}^{N}(x_{i}-{\displaystyle \textstyle {\bar {x}}}) ^{2} }](https://tex.z-dn.net/?f=s%3D%5Csqrt%5B%20%5D%7B%5Cfrac%7B1%7D%7BN-1%7D%20%5Csum_%7Bi%3D1%7D%5E%7BN%7D%28x_%7Bi%7D-%7B%5Cdisplaystyle%20%5Ctextstyle%20%7B%5Cbar%20%7Bx%7D%7D%7D%29%20%5E%7B2%7D%20%7D)
Where:
Sample standart deviation
Number of observations in the sample
Mean value of the sample
and
simbolizes the addition of the square of the difference between each observation and the mean value of the sample.
Let's start calculating the mean value:




Now, let's calculate the summation:


So, now we can calculate the standart deviation:
![s=\sqrt[ ]{\frac{1}{N-1} \sum_{i=1}^{N}(x_{i}-{\displaystyle \textstyle {\bar {x}}}) ^{2} }](https://tex.z-dn.net/?f=s%3D%5Csqrt%5B%20%5D%7B%5Cfrac%7B1%7D%7BN-1%7D%20%5Csum_%7Bi%3D1%7D%5E%7BN%7D%28x_%7Bi%7D-%7B%5Cdisplaystyle%20%5Ctextstyle%20%7B%5Cbar%20%7Bx%7D%7D%7D%29%20%5E%7B2%7D%20%7D)
![s=\sqrt[ ]{\frac{1}{15-1}*(2173160)}](https://tex.z-dn.net/?f=s%3D%5Csqrt%5B%20%5D%7B%5Cfrac%7B1%7D%7B15-1%7D%2A%282173160%29%7D)
![s=\sqrt[ ]{\frac{2173160}{14}}](https://tex.z-dn.net/?f=s%3D%5Csqrt%5B%20%5D%7B%5Cfrac%7B2173160%7D%7B14%7D%7D)

The sample standard deviation is 393.99