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Mila [183]
3 years ago
12

A pulley requires you to pull 3 times the amount of rope in order to lift an object. Therefore, the mechanical advantage is ____

_.
A. 1/3
B. 1
C. 3
D. 30
Physics
1 answer:
RideAnS [48]3 years ago
6 0
<h3>Answer:</h3>

1

<h3>Explanation:</h3>
  • A pulley is an example of a simple machine that is made up of ropes and wheels.
  • Mechanical advantage refers to the number of times that a simple machine multiplies the input force.
  • This means if a simple machine has a mechanical advantage of 5 then it means that it made the work done 5 times easier than without it.
  • It also means that one would apply 1/5 times the force they would have applied without the machine.
  • In this case, the pulley which is a simple machine requires you pull 3 times the amount of the rope. Therefore, the mechanical advantage of the machine is 1, which means the output force is equal to the input force.
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If the velocity of gas molecules is doubled the its kinetic energy will be
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A solution is a homogeneous mixture of one or more solutes dissolved in a solvent. A specific volume of solvent is only able to
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<h3><u>Answer;</u></h3>

C. Supersaturated

<h3><u>Explanation</u>;</h3>
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3 years ago
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What is the speed of sound for noise that travels 2 km in 5.8
earnstyle [38]

Answer:

2.9

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8 0
3 years ago
An isotropic point source emits light at wavelength 510 nm, at the rate of 170 W. A light detector is positioned 410 m from the
Wewaii [24]

Answer:

\frac{dB}{dt} = 3.03 \times 10^6 T/s

Explanation:

As we know that the power emitted by the source is given as

P = 170 W

now we know that

P = \frac{N}{t} (\frac{hc}{\lambda})

now we know that energy density is given as

u = \frac{B^2}{2\mu_0} + \frac{\epsilon_0 E^2}{2}

now we have

E = B c

u = \frac{B^2}{2\mu_0}

intensity is defined as

I = \frac{P}{A}

now we have

\frac{I}{c} = u = \frac{B^2}{2\mu_0}[/tex]

now we have

\frac{dB}{dt} = \omega B

\frac{dB}{dt} = \frac{2\pi c B}{\lambda}

\frac{dB}{dt} = \frac{2\pi c \sqrt{2\mu_0 I}}{\lambda\sqrt c}

here we have

I = \frac{P}{4\pi r^2}

I = \frac{170}{4\pi (410)^2}

I = 8.05 \times 10^{-5}

now we have

\frac{dB}{dt} = \frac{2\pi\sqrt{2\mu_0 c (8.05 \times 10^{-5})}}{(510 nm)}

\frac{dB}{dt} = 3.03 \times 10^6 T/s

4 0
3 years ago
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