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Nimfa-mama [501]
2 years ago
11

6. The momentum of a 30.0 g bird with a speed of 12 m.s-1 is 0.36 kg.m.s-1. What will be its momentum 12s later if a constant .0

2 N force due to air resistance acts on it
Physics
1 answer:
Keith_Richards [23]2 years ago
7 0

Answer:

Explanation:

initial momentum = .36 kg.m.s⁻¹

negative impulse = force x time = .02 x 12 = .24 kg.m.s⁻¹

final momentum - initial momentum = impulse

final momentum = initial momentum + impulse

= .36 - .24

= .12 kg.m.s⁻¹

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yawa3891 [41]

Answer:

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Explanation:

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Where

T is the period in seconds

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Where i and h stand for initial and final values.
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