Answer:
the work done by the lawnmower is 236.14 J.
Explanation:
Given;
power exerted by the lawnmower engine, P = 19 hp
time in which the power was exerted, t = 1 minute = 60 s.
1 hp = 745.7 watts
The work done by the lawnmower is calculated as follows;
Therefore, the work done by the lawnmower is 236.14 J.
During the fall, all the initial potential energy of the rock
has converted into kinetic energy of motion
where h is the initial height of the rock, m its mass, and v its velocity just before hitting the water. So, for energy conservation, we have
and so we can find the value of K, the kinetic energy of the rock just before hitting the ground:
Answer:
Yes
Explanation:
Just as motion in two dimensions introduced vectors, forces in two dimensions also involve more involved issues.
'Displacement' is the distance and direction between the starting point and
ending point, regardless of the path followed to get there.
A particle that's executing simple harmonic motion is always in the same place
where it was one time period ago, and where it will be later after another time
period has passed.
So its displacement during exactly one time period is exactly zero.
