K.E1=1/2×100×3²
=50×9
=450J
K.E2=1/2×100×36
=50×36
=1800J
The lens equation gives d relation between focal length, object distance n image distance.
1/f = 1/v + 1/u
seldon
Answer:
The ratio of the resistances of second coil to the first coil is the ratio of square of radius of the first coil to the square of radius of second coil.
And
The ratio of the resistances of fourth coil to the third coil is the ratio of square of radius of the third coil to the square of radius of fourth coil.
Explanation:
The resistance of the coil is directly proportional to the length of the coil and inversely proportional to the area of coil and hence inversely proportional to the square of radius of the coil.
So, the ratio of the resistances of second coil to the first coil is the ratio of square of radius of the first coil to the square of radius of second coil.
And
The ratio of the resistances of fourth coil to the third coil is the ratio of square of radius of the third coil to the square of radius of fourth coil.
The magnetic part using the Lorentz force is: F = q v x
B,
where v and B are vectors and v x B is the vector cross product.
Magnitude of the force: F = q v B sin(α)
So, sin(α) = F/( e v B), with e the proton charge.
This will give you a value for sin(α), and two potentials
for its opposite.
You will now look for:
sin(α) = 7.40 10^-13/( 1.60 10^-19 * 5 10^6 * 1.78)
= 0.520
So either sin(α) = 0.502 or sin(α) = -0.502
The 1st α = 30.1 degrees or α = 150 degrees.
The 2nd α = 210 degrees or α = 330 degrees.
So we can say that 30.1 degrees and 330 degrees would be minimum and biggest on [0,360]
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