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3 years ago

If a scale on Earth reads 650 N, what is your mass?

1 answer:

4 0

If the scale reads 650N, then the mass of whoever it is standing on the scale is

(weight) / (gravity) = (650N) / (9.8 m/s²) = 66.3 kilograms .

It's not MY mass, even if I'm the one standing on the scale.
If I stand on a scale and it reads 650 N, the scale is broken.

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The diagram shows a person holding a bow and arrow. Which will most likely increase the kinetic energy in this system? a not rel

Fantom [35]

Answer:

b. Increasing the mass of the arrow.

Explanation:

The formula is K=1/2mv^2. Increasing the mass also increases the kinetic energy.

7 0

3 years ago

A CO molecule has an intrinsic dipole moment whose magnitude is 4 X 10^-31 C*m. If the separation between the atoms is 0.11 nm,

aleksandrvk [35]

4x10^-31/(0.11x10^-9)= 3,63 x 10^-21

5 0

3 years ago

Can anyone answer this for me

horrorfan [7]

Answer:

answer what broski

Explanation

6 0

3 years ago

Un acróbata de 60 kg realiza un acto de equilibrio sobre un bastón. El extremo del bastón, en contacto con el piso, tiene un áre

vivado [14]

Answer:

Pressure, $P=6.39\times 10^6\ Pa$

Explanation:

A 60 kg acrobat performs a balancing act on a cane. The end of the cane, in contact with the floor, has an area of 0.92 cm2. Calculate the pressure the cane exerts on the floor (neglect the weight of the cane).

We have,

Mass of acrobat, m = 60 kg

The end of the cane, in contact with the floor, has an area of, $A=0.92\ cm^2=0.92\times 10^{-4}\ m^2$

It is required to find the the pressure the cane exerts on the floor. Pressure exerted by an object is defined as the force acting per unit its area. Its formula is written as :

$P=\dfrac{F}{A}\\\\P=\dfrac{mg}{A}\\\\P=\dfrac{60\times 9.8}{0.92\times 10^{-4}}\\\\P=6.39\times 10^6\ Pa$

So, the pressure the cane exerts on the floor is $6.39\times 10^6\ Pa$ .

3 0

3 years ago

A stone is thrown vertically upwards with an intinal velocity of 20 m/sec . find the maximum height it reaches and the time by i

serious [3.7K]

Answer:

Maximum height is20m and time taken will be 2second

Explanation:

vi=20m/s

vf=0m/s

g=10m/s^2

Using third equation for objects falling freely

2gh=(vf)^2-(vi)^2

Putting values

2(10m/s^2)h=(0m/s)^2-(20m/s)^2

20h=400m

h=20m

Now we have to find the time

Using first equation of motion for objects falling down freely

vf=vi+at

substituting the equation

(vf-vi)/g=t

(0-20)/10=t

t=2second

4 0

3 years ago