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julsineya [31]
3 years ago
9

What phenomena provides evidence of electric fields in the atmosphere

Physics
1 answer:
diamong [38]3 years ago
5 0
The phenomena<span> of </span>atmospheric<span> electricity are of three kinds. ..... In the Earth-</span>ionosphere cavity, the electric field<span> and conduction current in the lower </span>atmosphere<span> </span>
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A Carnot engine operates with a cold reservoir at a temperature of 474 K and a hot reservoir at a temperature of 628 K. What is
Zigmanuir [339]

Answer:

zero

Explanation:

A Carnot engine is an ideal engine in which the process is cyclic and reversible.

A Carnot engine is the engine whose efficiency is 100 % and the entropy in is equal to entropy out. That means the net change in entropy is zero.

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3 years ago
el of a Shs when places in water. The same piece of day ficas ftis made into the stage of a boat. Why does the day ficat when ma
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If my truck loses a ski, and the sky is yellow, then how many ounces of milk will I need to make a house?
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3 years ago
The kinetic energy of a rotating body is generally written as K=12Iω2, where I is the moment of inertia. Find the moment of iner
stira [4]

Answer:

See explanation

Explanation:

We have a mass m revolving around an axis with an angular speed \omega, the distance from the axis is r. We are given:

\omega = 10 [rad/s]\\r=0.5 [m]\\m=13[Kg]

and also the formula which states that the kinetic rotational energy of a body is:

K =\frac{1}{2}I\omega^2.

Now we use the kinetic energy formula

K =\frac{1}{2}mv^2

where v is the tangential velocity of the particle. Tangential velocity is related to angular velocity by:

v=\omega r

After replacing in the previous equation we get:

K =\frac{1}{2}m(\omega r)^2

now we have the following:

K =\frac{1}{2}m(\omega r)^2 =\frac{1}{2}Iw^2

therefore:

mr^2=I

then the moment of inertia will be:

I = 13*(0.5)^2=3.25 [Kg*m^2]

3 0
3 years ago
Does a falling rock have potential or kinetic energy
Neko [114]

depends t what stage in the fall it is. If it is at the peak, it is fully potential. If it is in the middle, it has both. If it is at the bottom of the fall, it is completely kinetic

3 0
3 years ago
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A geosynchronous satellite moves in a circular orbit around the Earth and completes one circle in the same time T during which t
andreyandreev [35.5K]

Answer:

Explanation:

The time period of geosynchronous satellite must be equal to T .

The radius of its orbit will be (  R+ h )

orbital velocity  V₀ =  \sqrt{\frac{GM}{( R+h)} }

Time period T = 2π( R + h ) / V₀

= 2π( R + h ) x \sqrt{\frac{( R+h)}{GM } }

\frac{T^\frac{2}{3}(GM)^\frac{1}{3}  }{(2\pi )^\frac{2}{3} } = R +h

h = \frac{T^\frac{2}{3}(GM)^\frac{1}{3}  }{(2\pi )^\frac{2}{3} } - R.

7 0
3 years ago
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