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gtnhenbr [62]
3 years ago
13

Which one is it (it’s multiple choice too)

Chemistry
1 answer:
ArbitrLikvidat [17]3 years ago
5 0

Answer:

i think its b and c.

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Hard water often contains dissolved Mg2+and Ca2+ions. Water softeners often use sodium carbonate to soften the water. Sodium car
Dvinal [7]

Answer:

32.5g of sodium carbonate

Explanation:

Reaction of sodium carbonate (Na₂CO₃) with Mg²⁺ and Ca²⁺ as follows:

Na₂CO₃(aq) + Ca²⁺(aq) → CaCO₃(s)

Na₂CO₃(aq) + Mg²⁺(aq) → MgCO₃(s)

<em>1 mole of carbonate reacts per mole of the cations.</em>

<em />

To know the mass of sodium carbonate we must know the moles of carbonate we need to add based on the moles of the cations:

<em>Moles Mg²⁺:</em>

2.91L * (0.0661 moles MgCl₂ / 1L) = 0.192 moles MgCl₂ = Moles Mg²⁺

<em>Moles Ca²⁺:</em>

2.91L * (0.0396mol Ca(NO₃)₂ / 1L) = 0.115 moles Ca(NO₃)₂ = Moles Ca²⁺

That means moles of sodium carbonate you must add are:

0.192 moles + 0.115 moles = 0.307 moles sodium carbonate.

In grams (Using molar mass Na₂CO₃ = 105.99g/mol):

0.307 moles Na₂CO₃ * (105.99g / mol) =

<h3>32.5g of sodium carbonate</h3>
3 0
3 years ago
How many grams of solute are needed to make 2.50 L of a 1.75 M solution of Ba(NO3)2?
Eddi Din [679]

1143.4grams of solute are needed to make 2.50L of a 1.75M solution of Ba(NO3)2. Details about molarity can be found below.

<h3>How to calculate mass?</h3>

The mass of a substance can be calculated by multiplying the number of moles by its molar mass.

However, the number of moles can be calculated by using the following formula:

Molarity = no of moles ÷ volume

no of moles = 1.75 × 2.5

no of moles = 4.38mol

molar mass of Ba(NO3)2 = 261.34g/mol

mass of Ba(NO3)2 = 261.34 × 4.38

mass of Ba(NO3)2 = 1143.4grams.

Therefore, 1143.4grams of solute are needed to make 2.50L of a 1.75M solution of Ba(NO3)2.

Learn more about mass at: brainly.com/question/19694949

3 0
2 years ago
What is the molarity of a solution of h3po4 if 10.2 ml is neutralized by 53.5 ml of 0.20m koh what is the molarity of a solution
Anna35 [415]

The molarity of the solution of H₃PO₄ needed to neutralize the KOH solution is 0.35 M

<h3>Balanced equation </h3>

H₃PO₄ + 3KOH —> K₃PO₄ + 3H₂O

From the balanced equation above,

  • The mole ratio of the acid, H₃PO₄ (nA) = 1
  • The mole ratio of the base, KOH (nB) = 3

<h3>How to determine the molarity of H₃PO₄ </h3>
  • Volume of acid, H₃PO₄ (Va) = 10.2 mL
  • Molarity of base, Ca(OH)₂ (Mb) = 0.2 M
  • Volume of base, Ca(OH)₂ (Vb) = 53.5 mL
  • Molarity of acid, H₃PO₄ (Ma) =?

MaVa / MbVb = nA / nB

(Ma × 10.2) / (0.2 × 53.5) = 1 / 3

(Ma × 10.2) / 10.7 = 1 / 3

Cross multiply

Ma × 10.2 × 3 = 10.7

Ma × 30.6 = 10.7

Divide both side by 30.6

Ma = 10.7 / 30.6

Ma = 0.35 M

Learn more about titration:

brainly.com/question/14356286

#SPJ1

8 0
2 years ago
Why do solids maintain a specific shape and volume?
s344n2d4d5 [400]

Answer:

Solids can hold their shape because their molecules are tightly packed together. ... Atoms and molecules in liquids and gases are bouncing and floating around, free to move where they want. The molecules in a solid are stuck in a specific structure or arrangement of atoms.

<em>Hope it helps...</em>

5 0
3 years ago
How many grams of a stock solution that is 92.5 percent H2SO4 by mass would be needed to make 250 grams of a 35.0 percent by mas
IrinaVladis [17]

94.6 g.  You must use 94.6 g of 92.5 % H_2SO_4 to make 250 g of 35.0 % H_2SO_4.

We can use a version of the <em>dilution formula</em>

<em>m</em>_1<em>C</em>_1 = <em>m</em>_2<em>C</em>_2

where

<em>m</em> represents the mass and

<em>C</em> represents the percent concentrations

We can rearrange the formula to get

<em>m</em>_2= <em>m</em>_1 × (<em>C</em>_1/<em>C</em>_2)

<em>m</em>_1 = 250 g; <em>C</em>_1 = 35.0 %

<em>m</em>_2 = ?; _____<em>C</em>_2 = 92.5 %

∴ <em>m</em>_2 = 250 g × (35.0 %/92.5 %) = 94.6 g

4 0
3 years ago
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