Answer:
![p_O=818.2torr](https://tex.z-dn.net/?f=p_O%3D818.2torr)
Explanation:
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In this case, according to the given equation, it is possible to calculate the mass of oxygen by using the Dalton's law, considering that the total pressure is 850 torr and the vapor pressure of water at 30°C is 31.8 torr:
![P_T=p_O+p_{H_2O}](https://tex.z-dn.net/?f=P_T%3Dp_O%2Bp_%7BH_2O%7D)
Thus, we solve for the pressure of oxygen as follows:
![p_O=P_T-p_{H_2O}\\\\p_O=850torr-31.8torr\\\\p_O=818.2torr](https://tex.z-dn.net/?f=p_O%3DP_T-p_%7BH_2O%7D%5C%5C%5C%5Cp_O%3D850torr-31.8torr%5C%5C%5C%5Cp_O%3D818.2torr)
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The balanced chemical reaction describing this decomposition is as follows:
<span>4c3h5n3o9 .............> 6N2 + 12CO2 +10H2O + O2
From the periodic table:
mass of oxygen = 16 grams
mass of nitrogen = 14 grams
mass of hydrogen = 1 gram
mass of carbon = 12 grams
Therefore:
mass of </span><span>C3H5N3O9 = 3(12) + 5(1) + 3(14) + 9(16) = 227 grams
mass of O2 = 2(16) = 32 grams
From the balanced chemical equation:
4(227) = 908 grams of </span>C3H5N3O9 produce 32 grams of O2. Therefore, to know the amount of oxygen produced from 4.5*10^2 grams <span>C3H5N3O9, all we need to do is cross multiplication as follows:
amount of oxygen = (4.5*10^2*32) / (908) = 15.859 grams</span>
1 kilo joule = 0.239006 calories
134 kilo joule = 134 x 0.239006
= 32.026804 calories