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daser333 [38]
2 years ago
8

What are the errors in this table check all that apply

Chemistry
1 answer:
Marat540 [252]2 years ago
4 0

Answer:

Cannot be determined

Explanation:

Hi there,

Could you please add an attachment of the table? We cannot tell what the errors are if there is no table.

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Give the number of significant figures indicated 78
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2 significant figures

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An astronomer studying planets outside our solar system has analyzed the atmospheres of four planets. Which of these planets’ at
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Answer: Planet A: 76% Nitrogen, 23% Oxygen, 1% Other

Explanation: Hope this helps!

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Define atmpospheric pressure
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5 0
3 years ago
A 10,0-L cylinder of gas is stored at room temperature (20.0°C) and a pressure of 1800 psi. If the gas is
makvit [3.9K]

Considering the Charles' law, the gas would have a temperature of -109.2 C.

<h3>Charles' law</h3>

Finally, Charles' law establishes the relationship between the volume and temperature of a gas sample at constant pressure. This law says that the volume is directly proportional to the temperature of the gas. That is, if the temperature increases, the volume of the gas increases, while if the temperature of the gas decreases, the volume decreases.

Charles' law is expressed mathematically as:

\frac{V}{T} =k

If you want to study two different states, an initial state 1 and a final state 2, the following is true:

\frac{V1}{T1} =\frac{V2}{T2}

<h3>Temperature of the gas in this case</h3>

In this case, you know:

  • P1= 1800 psi
  • V1= 10 L
  • T1= 20 C= 293 K (being 0 C= 273 K)
  • P2= 1800 psi
  • V2= 6 L
  • T2= ?

You can see that the pressure remains constant, so you can apply Charles's law.

Replacing in the Charles's law:

\frac{10 L}{293 K} =\frac{6 L}{T2}

Solving:

\frac{10 L}{293 K} T2=6 L

T2=\frac{6 L}{\frac{10 L}{293 K} }

<u><em>T2=163.8 K= -109.2 C</em></u>

The gas would have a temperature of -109.2 C.

Learn more about Charles's law:

brainly.com/question/4147359?referrer=searchResults

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2 years ago
What is the molarity of a 500.0 ml solution containing 0.75 moles of solute?
wariber [46]
M=mol/L
M=.75/.5
M=1.5
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3 years ago
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