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3 years ago

A total of 750 j of work was done when a force of 125 n was exerted on a box to move it. how far was the box moved?

1 answer:

3 0

Work = Force times Distance
W = Fd

Given W = 750J, F = 125N;

750 = 125d

Solving for d:
d = 750/125
d = 6

The box moved a distance of 6 meters.

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Monitoring cash flow and keeping track of the bottom line of a business are responsibilities for whom?

lina2011 [118]

Answer:
A financial manager.

Explanation:
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2 years ago

Check all that are true about waterfalls

Lerok [7]

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3 years ago

A 3874-kg rollercoaster is brought to the top of a 42m hill in 40 seconds,then drops 28m before the next hill.

Ede4ka [16]

(a) The work required to get the coaster to the top of the first hill is 1,594,538.4 J.

(b) The power required to bring the train to the top of the first hill is 39,863.46 W.

(d) The left at the bottom is determined as 1,063,025.6 J.

<h3>Work done to bring the rollercoaster top of the hill</h3>

W = Fn x d = mgh

W = 3874 x 9.8 x 42

W = 1,594,538.4 J

<h3>Power dissipated in bringing the rollercoaster on top hill</h3>

P = Fv

P = Fd/t

P = W/t

P = 1,594,538.4 /40 = 39,863.46 W

<h3>Energy lost when the coaster drops</h3>

E = 1,594,538.4 - (3874 x 9.8 x 28)

E = 531,512.8 J

<h3>Energy left at the bottom</h3>

E = 3874 x 9.8 x 28 = 1,063,025.6 J

Learn more about energy here: brainly.com/question/13881533

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6 0

2 years ago

Visible light is an example of which type of energy?

sergiy2304 [10]

Answer:

Hello There!!

Explanation:

The answer is A. electromagnetic.

hope this helps,have a great day!!

~Pinky~

8 0

3 years ago

Read 2 more answers

An electron is moving at 7.4x105 m/s perpendicular to a magnetic field. It experiences a force of 2.0x10–13 N. What is the magne

alisha [4.7K]

Answer:

1.69 T

Explanation:

Applying,

F = BvqsinФ.................. Equation 1

Where F = Force, B = magnetic field, v = velocity, q = charge on an electron, Ф = angle between the electron and the field.

make B the subject of the equation,

B = F/(vqsinФ)............. Equation 2

From the question,

Given: F = 2.0×10⁻¹³ N, v = 7.4×10⁵ m/s, Ф = 90°

Constant: q = 1.60×10⁻¹⁹ C

Substitute into equation 2

B = 2.0×10⁻¹³/(7.4×10⁵×1.60×10⁻¹⁹×sin90°)

B = 0.169×10

B = 1.69 T

4 0

2 years ago