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Nimfa-mama [501]
3 years ago
15

Can someone define 'work' for me please? I looked it up but there are a lot of different answers. The physics type, not a job :)

Physics
1 answer:
Sergio [31]3 years ago
6 0

Answer:

in physics, work is the energy transferred to or from an object via the application of force along a displacement. In its simplest form, it is often represented as the product of force and displacement.

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To withstand ‘g-forces’ of up to 10 g’s, caused by suddenly pulling out of a steep dive, fighter jet pilots train on a ‘human ce
Marina86 [1]

Answer:

34.292 m/s

Explanation:

When plane dives the gravitational acceleration becomes 10 times extra i-e

acceleration a = g= 10g's=10 ×9.8= 98 m/sec2

radius of dive circle = 12 m

v= speed= ?

Using

a= \frac{v^{2} }{r}

==> v^{2} = a × r = 98 × 12 = 1176 (\frac{m}{s}) ^{2}

==> v= \sqrt{1176(\frac{m}{s} )^{2} }

==> v= 34.292 m/s

4 0
3 years ago
Given a force of 50 N and an acceleration of 5 m/s/s, what is the object’s mass?
damaskus [11]
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3 years ago
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where would a bowling ball and a napkin fall with the same acceleration. Check all that apply. A. Dropped off of the Leaning Tow
Kazeer [188]

Answer: here ya go

A Bowling ball and a napkin would fall with the same acceleration in space where there is vacuum. Basically where there is no drag force and the two objects are freely falling under gravity. The two objects would fall with same acceleration due to gravity.

Explanation:

7 0
3 years ago
Determine the ratio of the resistivity of pure water to silver?
kondor19780726 [428]

Answer:

3 \cdot 10^{11} : 1

Explanation:

Silver is a generally excellent conductor, this implies its resistivity is low (from table, we can check the exact worth i.e \rho_s = 1.6 \cdot 10^{-8} \Omega m)

Pure water, rather, is an extremely awful conductor, this implies its resistivity is exceptionally high, of order of k \Omega \cdot m (10^3 \Omega m )

Indeed, even without knowing the exact estimation of the pure water resistivity, we can appraise the proportion between the pure water resistivity and the silver resistivity by looking at the two orders of magnitude:

r= \frac{10^3 \Omega m}{10^{-8} \Omega m}  \sim 10^{11}

Therefore, we can say that the correct answer is

3 \cdot 10^{11} : 1

4 0
3 years ago
PLEASE HELP!! I'll mark brainliest for correct answer.
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