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4 years ago

15

What is the temperature at which the liquid reach the top of the straw or highest temperature you were able to get without the b

ottle overflowing

1 answer:

ivanzaharov [21]4 years ago

8 0

Answer:

Boiling point is 100 c

Explanation:

You might be interested in

A+10 u charge and a -10 4C (1 HC - 106 C), at a distance of 0.3 m,

Marina CMI [18]

Answer:

B. Attract each other with a force of 10 newtons.

Explanation:

Statement is incorrectly written. <em>The correct form is: A </em> $+10\,\mu C$ <em> charge and a </em> $-10\,\mu C$ <em> at a distance of 0.3 meters. </em>

The two particles have charges opposite to each other, so they attract each other due to electrostatic force, described by Coulomb's Law, whose formula is described below:

$F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}}$ (1)

Where:

$F$ - Electrostatic force, in newtons.

$\kappa$ - Electrostatic constant, in newton-square meters per square coulomb.

$|q_{A}|,|q_{B}|$ - Magnitudes of electric charges, in coulombs.

$r$ - Distance between charges, in meters.

If we know that $\kappa = 8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}$ , $|q_{A}| = |q_{B}| = 10\times 10^{-6}\,C$ and $r = 0.3\,m$ , then the magnitude of the electrostatic force is:

$F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}}$

$F = 9.987\,N$

In consequence, correct answer is B.

4 0

3 years ago

Kinetic energy is the energy of ______. It increases with mass ______ and _______ .Potential energy is the energy of _______or__

Alona [7]

Answer:

velocity. height. weight. possition. place. energy. force.

Explanation: 50/50 % chance they are wrong and write.

5 0

4 years ago

A block with mass of 10 kg is on a frictionless surface. One hand on the left side of the block is pushing it to the right. A se

igomit [66]

Answer:

$W_2=-12J$

Explanation:

The work of force 2 will be given by the vectorial equation $W_2=F_2.d$ . We know the value of $F_1$ and have information about its movement, which relates to the net force $F=F_1+F_2$ .

About this movement we can obtain the acceleration using the equation $v_f^2=v_i^2+2ad$ . Since it departs from rest we have $a=\frac{v_f^2}{2d}$ .

And then using Newton's 2dn Law we can obtain the net force F=ma, thus we will have $F_2=F-F_1=ma-F1=\frac{mv_f^2}{2d}-F_1$

And we had the work done by force 2 as:

$W_2=F_2.d=\frac{mv_f^2}{2}-F_1d$

(The sign will be given algebraically since we take positive the direction to the right.)

With our values:

$W_2=\frac{(10kg)(2m/s)^2}{2}-(8N)(4m)=-12J$

<em>Another (shorter but maybe less intuitive way for someone who is learning) way of doing this would have been to say that the work done by both forces would be equal to the variation of kinetic energy:</em>

<em> $W_1+W_2=K_f-K_i=K_f=\frac{mv_f^2}{2}$ </em>

<em>Which leads us to the previous equation straightforwardly.</em>

6 0

3 years ago

Steel wire rope is used to lift a heavy object. We use a 3.1m steel wire that

kaheart [24]

Answer:

Young's modulus for the rope material is 20.8 MPa.

Explanation:

The Young's modulus is given by:

$E = \frac{FL_{0}}{A\Delta L}$

Where:

F: is the force applied on the wire

L₀: is the initial length of the wire = 3.1 m

A: is the cross-section area of the wire

ΔL: is the change in the length = 0.17 m

The cross-section area of the wire is given by the area of a circle:

$A = \pi r^{2} = \pi (\frac{0.006 m}{2})^{2} = 2.83 \cdot 10^{-5} m^{2}$

Now we need to find the force applied on the wire. Since the wire is lifting an object, the force is equal to the tension of the wire as follows:

$F = T_{w} = W_{o}$

Where:

$T_{w}$ : is the tension of the wire

$W_{o}$ : is the weigh of the object = mg

m: is the mass of the object = 1700 kg

g: is the acceleration due to gravity = 9.81 m/s²

$F = mg = 1700 kg*9.81 m/s^{2} = 16677 N$

Hence, the Young's modulus is:

$E = \frac{16677 N*0.006 m}{2.83 \cdot 10^{-5} m^{2}*0.17 m} = 20.8 MPa$

Therefore, Young's modulus for the rope material is 20.8 MPa.

I hope it helps you!

7 0

3 years ago

While in europe, if you drive 125 km per day, how much money would you spend on gas in one week if gas costs 1.10 euros per lite

Ymorist [56]

First we need to write the data given in the problem.
Given Data
Distance per day = 125km
Gas cost =1.10 Eu per liter
Car mileage= 37.0 mil/gal
1 Eu= 1.26$
Find
1 week expenditure on Gas =?

Solution
Distance in one week = 125 kmx 7 = 875 km or 543.7 miles
Gas consumed in one week = 543.7/37 = 14.694 gal or 52.99 litre

Answer
Cost of Gas per week = 52.99 x 1.10 = 58.28 Eu or 73.44$

Regards

8 0

3 years ago