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Ivanshal [37]
3 years ago
15

What is the temperature at which the liquid reach the top of the straw or highest temperature you were able to get without the b

ottle overflowing
Physics
1 answer:
ivanzaharov [21]3 years ago
8 0

Answer:

Boiling point is 100 c

Explanation:

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Is there a link between number of bulbs and current drawn from the power pack?
Maurinko [17]

Answer:

Yes, there a link between number of bulbs and current drawn from the power pack.

Explanation:

In an Electrical circuit, we have resistors present in that circuit. These resistors can be connected in two ways.

a) Series connection

b) Parallel connection

There is a link or a relationship between number of bulbs and the current drawn from the power pack. This is because the number of bulbs is equivalent to or equal to the number of resistors.

Hence,

a) In a series connection, the link or relationship between the number of bulbs(resistors) is as the number of light bulbs increases, the current in the power pack (circuit) decreases.

b) In a parallel connection, the link or relationship between the number of bulbs(resistors) is as the number of light bulbs increases, the current in the power pack (circuit) increases.

5 0
3 years ago
A rock is suspended by a light string. When the rock is in air, the tension in the string is 51.9 N . When the rock is totally i
Luden [163]

Answer:

\rho _{liquid}=1995.07kg/m^{3}

Explanation:

When the rock is immersed in unknown liquid the forces that act on it are shown as under

1) Tension T by the string

2) Weight W of the rock

3) Force of buoyancy due to displaced liquid B

For equilibrium we have T_{3}+B = W_{rock}

T_{3}+\rho _{Liquid}V_{rock}g=W_{rock}.....(\alpha)

When the rock is suspended in air for equilibrium we have

T_{1}=W_{rock}....(\beta)

When the rock is suspended in water for equilibrium we have

T_{2} + \rho _{water}V_{rock}g=W_{rock}.....(\gamma)

Using the given values of tension and solving α,β,γ simultaneously for \rho _{Liquid} we get

W_{rock}=51.9N\\31.6+1000\times V_{rock}\times g=51.9N\\\\11.4+\rho _{liquid}V_{rock}g=51.9N\\\\

Solving for density of liquid we get

\rho _{liquid}=\frac{51.9-11.4}{51.9-31.6}\times 1000

\rho _{liquid}=1995.07kg/m^{3}

5 0
2 years ago
Sara walks part way around a swimming pool. she walks 50 yards north, then 20 yards east, then 50 yards south. the magnitude of
Semmy [17]
|---20----|
|            |
| 50       |50
|---D--->|
Start      End

Total displacement(D)  20 yards (East).
6 0
3 years ago
Read 2 more answers
2. A 5 year old child pushes with a force of 5 N to get a sumo wrestler to move, but the
Svetllana [295]

formula= W=f*d

w=work done

f=force

d=distance

w=f*d

w= 5n*0(does not budge)means does not move so distance is zero

w=5J

The work done by the children on the sumo wrestler is 5J

6 0
3 years ago
Newton’s first law says that if motion changes, then a force is exerted. Describe a collision in terms of the forces exerted on
ira [324]

Answer:

In collision between equal-mass objects, each object experiences the same acceleration, because of equal force exerted on both objects.

Explanation:

In a collision two objects, there is a force exerted on both objects that causes an acceleration of both objects. These forces that act on both objects are equal in magnitude and opposite in direction.

Thus, in collision between equal-mass objects, each object experiences the same acceleration, because of equal force exerted on both objects.

4 0
3 years ago
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