So, the recovery force of the spring is <u>2 N in the opposite direction of the pull</u>.
<h3>Introduction</h3>
Hi ! Here, I will help you about the spring recovery force. <u>The restoring force is the force that opposes the direction of the initial pull of the spring (either when the spring is pulled horizontally or vertically)</u>. The restoring force is strongly influenced by the type of spring (through the spring constant) and the length of the strain that occurs. Negative values in spring restoring force only indicate direction, not value. The equation that applies is as follows:
If the spring is pulled horizontally
With the following condition :
- F = recovery force (N)
- k = spring constant (N/m)
- = horizontal length change (m)
If the spring is pulled vertically
With the following condition :
- F = recovery force (N)
- k = spring constant (N/m)
- = vertical length change (m)
<h3>Problem Solving</h3>
We know that :
- Assume the spring is pulled horizontally
- k = spring constant = 4 N/m
- = horizontal length change = 0.5 m
What was asked :
- F = recovery force = ... N
Step by step :
<h3>Conclusion :</h3>
So, the recovery force of the spring is 2 N in the opposite direction of the pull.
The distance between two successive high points in a wave is called a wavelength
Answer: Heat moves in three ways: Radiation, conduction, and convection.
Answer:
Reverse Osmosis and UV Treatment
Explanation:
Reverse Osmosis, commonly known as RO, process is very effective in removing salt content from water. This process is known as desalination. IN RO, a partially permeable membrane is used to remove unwanted molecules, ions, and large particles. RO will take care of both desalination and purification of water.
Further UV treatment can be done to kill any remaining microorganisms as these microorganisms can not withstand UV radiation.
We are to solve for the net electric field (E) given that there were two electrical charges at point A and B. The given values are the following:
Ea (at point A) = 7.1 x 10^5 newtons/coulomb
Eb (at point B) =2.2 x 10^5 newtons/coulomb
Solving for the net charge, we have:
E = Ea + Eb
E = 7.1x10^5 + 2.2 x10^5
E = 9.3 x 10^5 Newtons/Coulomb
The net electric field is 9.3 x10^5 Newtons/Coulombs.