Question

? A point P is on a line segment, which has two electrical charges, A and B, as its end points. If the electric field at point P due to charge A is +7.1 × 105 newtons/coulomb and the field due to charge B is +2.2 × 105 newtons/coulomb, what is the net electric field at point P?

Answer 1

We are to solve for the net electric field (E) given that there were two electrical charges at point A and B. The given values are the following:
Ea (at point A) = 7.1 x 10^5 newtons/coulomb
Eb (at point B) =2.2 x 10^5 newtons/coulomb
Solving for the net charge, we have:
E = Ea + Eb
E = 7.1x10^5  + 2.2 x10^5
E = 9.3 x 10^5 Newtons/Coulomb

The net electric field is 9.3 x10^5 Newtons/Coulombs.