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skad [1K]
3 years ago
10

Which of the following electron configurations for neutral atoms is correct?

Physics
2 answers:
Lynna [10]3 years ago
8 0

Answer:

nitrogen: 1s2, 2s2, 2p3 is correct answer.

Explanation: I got this answer correct on my quiz!!!

liq [111]3 years ago
6 0
Nitrogen: 1s2, 2s2, 2p3 is correct answer.
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A ball is thrown vertically up from the edge of a cliff with a speed of 8 m/s, how high is
anygoal [31]

Explanation:

s=d/t

d=s×t

d=8×16.4

d=131.2

distance is 131.2m.

7 0
3 years ago
You and a friend frequently play a trombone duet in a jazz band. During such performances it is critical that the two instrument
Rashid [163]

Answer:

f₂ = 468.67 Hz

Explanation:

A beat is a sudden increase and decrease of sound. The beats are produced through the interference of two sound waves of slightly different frequencies. Now we have the following data:

The higher frequency tone = f₁ = 470 Hz

No. of beats = n = 4 beats

Time period = t = 3 s

The lower frequency note = Frequency of Friend's Trombone = f₂ = ?

Beat Frequency = fb

So, the formula for beats per second or beat frequency is given as:

fb = n/t

fb = 4 beats/ 3 s

fb = 1.33 Hz

Another formula for beat frequency is:

fb = f₁ - f₂

f₂ =  f₁ - fb

f₂ = 470 Hz - 1.33 Hz

<u>f₂ = 468.67 Hz</u>

6 0
3 years ago
A train travels 85 kilometers in 5 hours, and then 63 kilometers in 5 hours what is its average speed?
Lesechka [4]
We know average speed =total distance/time taken
So avg speed=(85+63)/(5+5)=14.8km/hr
3 0
3 years ago
A solid, horizontal cylinder of mass 18.0 kg and radius 1.70.0 m rotates with an angular speed of 40 rad/s about a fixed vertica
Radda [10]

Answer:39.88 rad/s

Explanation:

Given

mass of cylinder m_1=18 kg

radius R=1.7 m

angular speed \omega =40rad/s

mass of m_2=0.8 kg dropped at r=0.3 m from center

let \omega _2 be the final angular velocity of cylinder

Conserving Angular momentum

L_1=L_2

\left ( \frac{m_1R^2}{2}\right )\omega =\left ( \frac{m_1R^2}{2}+m_2r^2\right )\omega _2

\left ( \frac{18\cdot 1.7^2}{2}\right )\cdot 40=\left ( \frac{18\cdot 1.7^2}{2}+0.8\cdot 0.3^2\right )\omega _2

26.01\times 40=26.082\times \omega _2

\omega _2=39.88 rad/s

3 0
3 years ago
Do true blackbodies exist in nature?<br><br> Yes or No??
MaRussiya [10]

Answer:

no

Explanation:

4 0
3 years ago
Read 2 more answers
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