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spin [16.1K]
3 years ago
13

Hey what is Krichoff rulegood morning​

Physics
2 answers:
Mekhanik [1.2K]3 years ago
3 0

Explanation:

sorry I've got a bad hand writing but i think ull understand more with the screenshot that I've just pinned for u there

nalin [4]3 years ago
3 0

Answer:

this guy has answed ur question lol

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Antonina throws a coin straight up from a height of
vichka [17]

Answer:

s=vt-\frac{1}{2}gt^2

Explanation:

We could use the following suvat equation:

s=vt-\frac{1}{2}gt^2

where

s is the vertical displacement of the coin

v is its final velocity, when it hits the water

t is the time

g is the acceleration of gravity

Taking upward as positive direction, in this problem we have:

s = -1.2 m

g=-9.8 m/s^2

And the coin reaches the water when

t = 1.3 s

Substituting these data, we can find v:

v=\frac{s}{t}+\frac{1}{2}gt=-\frac{1.2}{1.3}+\frac{1}{2}(-9.8)(1.3)=-7.3 m/s

where the negative sign means the direction is downward.

5 0
3 years ago
A 45-gram object that has a volume of 9 mL has a density of
yanalaym [24]

Answer:

<h2>  The answer is </h2><h2>a. 5g/mL</h2>

Explanation:

Given data

mass m= 45g

volume v= 9mL

we know that density=m/v

substituting our given data we have

density=\frac{45}{9} =5g/mL

What is Density?

The Density of a body can be defined as the ratio of mass to volume,

or

Density, mass of a unit volume of a material substance. The formula for density is Density= \frac{mass}{volume},

where d is density,

M is mass, and

V is volume.

Density is commonly expressed in units of grams per cubic centimetre.

7 0
3 years ago
Sara and Greg built an electromagnet in science class. They wrapped 50 turns of copper wire around an iron nail and hooked the e
Iteru [2.4K]

Answer:Wrap more turns of wire around the nail.

Explanation:The power of an electromagnet is directly proportional to the amount of electricity passing through that electromagnet.

Now,if they increase the number of rounds of the copper coil,the electricity conducting surface amount will also increase.

And that's why the electricity passing through that electromagnet will increase along with the electromagnetic power of that electromagnet.

• Increasing the battery voltage :

If they increase the battery voltage,the electricity which is passing through that electromagnet will also increase in amount .

And as discussed previously,the increasing amount of electricity will also increase the electromagnetic abilities of the electromagnet.

4 0
3 years ago
Read 2 more answers
Circuits
marusya05 [52]

Answer:

ഹലോ എങ്ങനെയുണ്ട് ക്ഷമിക്കണം എനിക്ക് ഉത്തരം അറിയില്ല

7 0
3 years ago
Consider two identical objects released from rest high above the surface of Earth. (Neglect air resistance for this question.)
Nadusha1986 [10]

The question is missing its alternatives. Here is the complete question.

Consider two identical objects released from rest high above the surface of Earth. In Case 1, the object is released from a height above the surface of Earth equal to 1 Earth radius, and we measure its kinetic energy just before it hits the Earth to be K1. In Case 2, the obejct is released from a height above the surface of Earth equal to 2 Earth radii and its kinetic energy just before it hits is K2.

1. Compare the kinetic energy of the two objects just before they hit the surface of the earth.

a) K2 = 2K1; b) K2 = 4K; c) K2 = (4/3)K1; d) K2 = (3/2)K1;

Answer: C) K2 = (4/3)K1

Explanation: As it is related to the gravity of the Earth, the potencial energy is: U(r)= - \frac{G.Me.m}{r} + U₀

In this case, U₀=0, G is the universal gravitational constant, Me is the mass of Earth, m is the mass of the object and r is the distance between the center of the Earth and the object.

The potencial energy of an object of mass m on the surface of the Earth is:

Usurface = - \frac{G.Me.m}{Re}

The potencial energy of the object in Case 1 is

U1 = - \frac{G.Me.m}{2Re}

For the Case 2:

U2 = - \frac{G.Me.m}{3Re}

The potencial change in Case 1:

ΔU1 = - G.Me.m.(\frac{1}{Re}-\frac{1}{2Re}) = - \frac{1}{2}\frac{G.Me.m}{Re}

For Case 2:

ΔU2 = - G.Me.m(\frac{1}{Re}-\frac{1}{3Re}) = - \frac{2}{3}\frac{G.Me.m}{Re}

Comparing ΔK1 and ΔK2 equals comparing ΔU1 and ΔU2:

Δ\frac{U2}{U1} = (-2/3)(-1/2) = 4/3

So, comparing kinetic energies, K2 is 4/3 of K1.

5 0
4 years ago
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