Ask question

Ask question

All categories

2 years ago

6

on the morning of an important game, gail woke up at 4:25. she wanted to wake up 2 hours 35 minutes later. what time did gail wa

nt to wake up?

1 answer:

polet [3.4K]2 years ago

7 0

Answer:

7:00

Step-by-step explanation:

4:25 + 2:35 = 7:00

60 minutes in one hour.

You might be interested in

A particle moving in a planar force field has a position vector x that satisfies x'=Ax. The 2×2 matrix A has eigenvalues 4 and 2

andrey2020 [161]

Answer:

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

Step-by-step explanation:

Consider the provided matrix.

$v_1=\begin{bmatrix}-3\\1 \end{bmatrix}$

$v_2=\begin{bmatrix}-1\\1 \end{bmatrix}$

$\lambda_1=4, \lambda_2=2$

The general solution of the equation $x'=Ax$

$x(t)=c_1v_1e^{\lambda_1t}+c_2v_2e^{\lambda_2t}$

Substitute the respective values we get:

$x(t)=c_1\begin{bmatrix}-3\\1 \end{bmatrix}e^{4t}+c_2\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}$

$x(t)=\begin{bmatrix}-3c_1e^{4t}-c_2e^{2t}\\c_1e^{4t}+c_2e^{2t} \end{bmatrix}$

Substitute initial condition $x(0)=\begin{bmatrix}-6\\1 \end{bmatrix}$

$\begin{bmatrix}-3c_1-c_2\\c_1+c_2 \end{bmatrix}=\begin{bmatrix}-6\\1 \end{bmatrix}$

Reduce matrix to reduced row echelon form.

$\begin{bmatrix} 1& 0 & \frac{5}{2}\\ 0& 1 & \frac{-3}{2}\end{bmatrix}$

Therefore, $c_1=2.5,c_2=1.5$

Thus, the general solution of the equation $x'=Ax$

$x(t)=2.5\begin{bmatrix}-3\\1\end{bmatrix}e^{4t}-1.5\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}$

$x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

6 0

3 years ago

Can you help me find the volume of this cube???

rewona [7]

Answer:

The answer is 15^3

Step-by-step explanation:

L*W*H

4*1 1/2*2 1/2

8 0

3 years ago

Read 2 more answers

What is the percent change if the student population of the school goes from 380 students to 335 students? Round to the nearest

lys-0071 [83]

Answer:

12% decrease

Step-by-step explanation:

I'm srry if I'm wrong but I'm 90-ish% its correct

6 0

3 years ago

Read 2 more answers

{[20/(8+2)]^6+6}/(4^2/2)

Naddika [18.5K]

So for this problem we need to do order of operations so the very first step that we need to do here is (8+2) because that is the smallest enclosed symbols (8+2)=10 next divide by 20 because that is the next step in the equation which 20/10=2, so now we have {[2]^6+6} and due to order of operations the next step here is to take 2 to the power of 6 which is 64 so now we have {64+6} which is 70 so now we have 70/(4^2/2) and due to order of operations we do the parentheses first and that would mean that we do 4^2 because exponents come after parantheses like so,
70/(16/2) now we do 16/2 because its still inside the paranthesess so 16/2=8 so now we have 70/8 and that equals are end answer of 8.75 Enjoy!=)

7 0

2 years ago

Read 2 more answers

PLZ NEED HELP ASAP SHOW WORK TO PLZ IT WOULD MEAN A LOT

Marizza181 [45]

First Chart: Perimeter

Square Portion:

Original Side Lengths: P = 4 (1 + 1 + 1 + 1 ) =4

Double Side Lengths: P = 8 (2 x 4 = 8)

Triple Side Lengths: P = 12 (4 x 3 = 12)

Quadruple Side Lengths: P = 16 (4 x 4 = 16)

Rectangle Portion:

Original Side Lengths: P = 6 (1 x 2 + 2 x 2 = 6)

Double Side Lengths: P = 12 (2 x 2 + 4 x 2 = 12)

Triple Side Lengths: P = 24 (4 x 2 + 8 x 2 = 24)

Quadruple Side Lengths: P = 48 (8 x 2 + 16 x 2 = 48)

Second Chart: Area

Square Portion:

Original Side Lengths: A = 1 (1 x 1 = 1)

Double Side Lengths: A = 4 (2 x 2 = 4)

Triple Side Lengths: A = 9 (3 x 3 = 9

Quadruple Side Lengths: A = 16 ( 4 x 4 = 16)

Rectangle Portion:

Original Side Lengths: A = 2 ( 1 x 2 = 2 )

Double Side Lengths: A = 8 ( 2 x 4 = 8)

Triple Side Lengths: A = 18 ( 3 x 6 = 18)

Quadruple Side Lengths: A = 32 (4 x 8 = 32)

7 0

2 years ago