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IceJOKER [234]
3 years ago
6

on the morning of an important game, gail woke up at 4:25. she wanted to wake up 2 hours 35 minutes later. what time did gail wa

nt to wake up?
Mathematics
1 answer:
polet [3.4K]3 years ago
7 0

Answer:

7:00

Step-by-step explanation:

4:25 + 2:35 = 7:00

60 minutes in one hour.

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Pls help I’m failing do it on paper and put it in the answer box
mina [271]

Step-by-step explanation:

there is no mathematical problem to solve.

just follow the instructions as given.

this is an exercise for you to get a feeling about what is what. it is imperative that you do it.

there is really nothing to solve.

remember, that a positive slope means the line goes up (from left to right), and a negative slope means the line goes down (again from left to right).

and I am sure you know what vertical and horizontal means.

7 0
2 years ago
the cost of four scarves and six hats is 52$. the cost of two hats is$1 more then the cost of one scarf. what are the costs of s
Katena32 [7]

Answer:

is thier anwser chocies?

Step-by-step explanation:


7 0
2 years ago
What is the average rate of change from x = 0 to x = 4?
hammer [34]
1) find the corresponding y values for when x = 0 and when x = 4,
when x = 0, y = 4
when x = 4, y = 4

the coordinates are (0,4) and (4,4)

2) to calculate the average rate of change, find the slope of the two points:

(0,4) (4,4)

(change in y) 4 - 4 = 0
(change in x) 4 - 0 = 4

0/4 = 0

the average rate of change is 0!
3 0
3 years ago
Deshawn has two bags of marbles. The first bag has 2 blue, 3 orange, and 5 red. The second bag has 4 pink, 10 blue, and 6 brown.
madreJ [45]

Answer: 0.1

Step-by-step explanation:

Given

Bag-I has 2 blue,3 orange, 5 red

Bag-II has 4 Pink,10 blue, 6 brown

No of ways of choosing a blue marble from bag-I

\Rightarrow ^2C_1

Total no of ways of choosing a marble from bag-I

\Rightarrow ^{10}C_1

No of ways of choosing a blue marble from bag-II

\Rightarrow ^{10}C_1

Total no of ways of choosing a marble from bag-II

\Rightarrow ^{20}C_1

The probability that he will pull out a blue marble from each bag is

\Rightarrow P=\text{Probability of pulling a blue marble from bag-I}\times \text{Probability of pulling a blue out bag-II}

\Rightarrow P=\dfrac{^2C_1}{^{10}C_1}\times \dfrac{^{10}C_1}{^{20}C_1}\\\\\Rightarrow P=\dfrac{2}{10}\times \dfrac{10}{20}=\dfrac{1}{10}

3 0
3 years ago
Solve the following equation: lim x->0 sin3x/5x^3-4x.
goblinko [34]
Usual limit of sin is sinX/X--->1, when X--->0

sin3x/5x^3-4x=0/0?, sin3x/3x--->1 when x --->0, so sin3x/5x^3-4x=                    [3x. sin3x / 3x] /(5x^3-4x)=(sin3x / 3x) . (3x/5x^3-4x)
   =(sin3x / 3x) . (3/5x^2- 4)
finally lim  sin3x/5x^3-4x=lim (sin3x / 3x) .(3/5x^2- 4)=1x(3/-4)= - 3/4
                 x----->0            x---->0
3 0
3 years ago
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