Answer:
1)The dimensions you are solving for
length of the rectangular room
width of the rectangular room
2)Now let the length be L and the width be w then
the perimeter is 2L+2W
2L+ 2W = 24------------------------------(1)
Also, "Twice the length decreased by three times the width is 4 feet" can be written as
2L - 3W = 4-------------------------------------(2)
Solving (1) and (2) by elimination method, by subtraction
2L+ 2W = 24
2L - 3W = 4
(-) (-) (-)
----------------------------
0L +5W = 20
-----------------------------
5W = 20
W = 4--------------------------------------------(3)
Now by substitution method,substituting (3) in(1)
2L+ 2(4) = 24
2L + 8 = 24
2L = 24 -8
2L = 16
L = 8
Substituting in the original equation and rechecking the perimeter
=2(8) + 2(4)
=16 + 8
= 24
Thus the found dimensions are correct
3)The length of the room is 8 feet and the width of the room is 4 feet.
Last option on the bottom right
Yes you are doing it right because 7*5=35 and 8*3=24.
g(x) = 4x−8, find g(1/2)
Replace x with 1/2 and solve.
4(1/2) - 8
= 2 - 8
= -6
The answer is -6
9514 1404 393
Answer:
one solution
Step-by-step explanation:
There will be one solution if the left-side x-coefficient is different from the right-side x-coefficient.
Simplifying, we get ...
x + 1/2x -2 = 1/2x +6x -12
3/2x -2 = 13/2x -12
The left-side coefficient is 3/2, which is different from the right-side coefficient of 13/2. The equation will have one solution.
__
Add 12-3/2x to both sides to get ...
10 = 5x
2 = x . . . . . divide both sides by 5. This is the solution.