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snow_tiger [21]
3 years ago
6

Your friend is bragging about his motorcycle. He claims that it can go from a stopped position to 50 miles per hour in three sec

onds. He is describing the motorcycle's
speed.

acceleration.

velocity.

direction.
Physics
2 answers:
nalin [4]3 years ago
8 0
If the motorcycle can go from 0 to 50mph in 3 seconds the person is describing the motorcycle's acceleration. 
tensa zangetsu [6.8K]3 years ago
5 0

Answer:

acceleration

Explanation:

He is describing the acceleration of motorcycle.

Here the initial velocity is zero, final velocity is 50 miles / hr, time taken is 3 sec.

Convert miles per hour into metre per second.

50 miles / hr = 22.352 m/s

using first equation of motion,

v = u + a x t

a = \left ( \frac{v - u}{t} \right )

a = \left ( \frac{22.352 - 0}{3} \right )

a = 7.45 m/s^2

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<span>118 C The Clausius-Clapeyron equation is useful in calculating the boiling point of a liquid at various pressures. It is: Tb = 1/(1/T0 - R ln(P/P0)/Hvap) where Tb = Temperature boiling R = Ideal Gas Constant (8.3144598 J/(K*mol) ) P = Pressure of interest Hvap = Heat of vaporization of the liquid T0, P0 = Temperature and pressure at a known point. The temperatures are absolute temperatures. We know that water boils at 100C at 14.7 psi. Yes, it's ugly to be mixing metric and imperial units like that. But since we're only interested in relative pressure differences, it's safe enough. So P0 = 14.7 P = 14.7 + 12.3 = 27 T0 = 100 + 273.15 = 373.15 And for water, the heat of vaporization per mole is 40660 J/mol Let's substitute the known values and calculate. Tb = 1/(1/T0 - R ln(P/P0)/Hvap) Tb = 1/(1/373.15 K - 8.3144598 J/(K*mol) ln(27/14.7)/40660 J/mol) Tb = 1/(0.002679887 1/K - 8.3144598 1/K ln(1.836734694)/40660) Tb = 1/(0.002679887 1/K - 8.3144598 1/K 0.607989372/40660) Tb = 1/(0.002679887 1/K - 5.055103194 1/K /40660) Tb = 1/(0.002679887 1/K - 0.000124326 1/K) Tb = 1/(0.002555561 1/K) Tb = 391.3034763 K Tb = 391.3034763 K - 273.15 Tb = 118.1534763 C Rounding to 3 significant figures gives 118 C</span>
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3 years ago
A 30-g car rolls from a hill 12 cm high and is traveling at 154 cm/s as it travels along a 275 cm horizontal track. What is the
Bond [772]
Momentum of the car is 46.2 kgm/s
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3 years ago
Can someone explain this
Alborosie

Answer:

gravity

Explanation:

That would make the most sense from what I know

8 0
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A small bar of pure gold whose density is 19.3g/cm. Displaces 80 cm
nasty-shy [4]

Answer:

The mass of the gold bar is 1,544 g

Explanation:

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3 years ago
4 . A negative charge -0.450 exerts an upward 0.150N force on an unknown charge 0.250m directly below it . ( a ) what is the unk
Elodia [21]

(a) The unknown charge kept at distance 0.250m directly below  -0.450 charge is  2.315 x 10⁻¹² C.

(b) The magnitude of the force is 29.16 x 10¹² N.

<h3>What is electrostatic force?</h3>

The electrostatic force F between two charged objects placed distance apart is directly proportional to the product of the magnitude of charges and inversely proportional to the square of the distance between them.

F = kq₁q₂/r²

where k = 9 x 10⁹ N.m²/C²

Given is a negative charge -0.450 exerts an upward 0.150N force on an unknown charge 0.250m directly below it .

In equation of the magnitude of force, only the magnitude of charges are taken.

Substituting the values into the expression ,we get the charge

0.150 = (9 x 10⁹ x 0.450x q)/ (0.25)²

q = 2.315 x 10⁻¹² C

Thus, the magnitude of the unknown charge is 2.315 x 10⁻¹² C.

b)Let the unknown charge be  0.450C to exert on -450C.

Substituting the values into the expression ,we get the electrostatic force

F = kq₁q₂/r²

F = (9 x 10⁹ x 0.450x 0.450)/ (0.25)²

q = 2.315 x 10⁻¹² C

Thus, the magnitude of the force is 29.16 x 10¹² N.

Learn more about electrostatic force.

brainly.com/question/9774180

#SPJ1

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2 years ago
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