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3 years ago

The efficiency of conversion of glucose to ATP during glycolysis is approximately:

Physics

1 answer:

liraira [26]3 years ago

4 0

Answer: approximately 50%

Explanation:

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A puck moves 2.35 m/s in a -22 degree direction. A hockey stick pushes it for 0.215 s, changing its velocity to 6.42 m/s in a 50

Whitepunk [10]

Answer:

Displacement in Y direction is 0.434 m

Explanation:

initial velocity of the puck is 2.35 m/s at -22 degree

so here it is given as

$v_i = 2.35 cos22 \hat i - 2.35 sin22 \hat j$

$v_i = 2.18 \hat i - 0.88 \hat j$

final velocity is given as 6.42 m/s at 50 degree

so we have

$v_f = 6.42 cos50 \hat i + 6.42 sin50\hat j$

$v_f = 4.13 \hat i + 4.92\hat j$

now displacement in Y direction is given as

$\Delta y = \frac{v_f + v_i}{2}t$

$\Delta y = \frac{-0.88 + 4.92}{2} (0.215)$

$\Delta y = 0.434 m$

5 0

3 years ago

A block oscillating on a spring has a maximum speed of 20 cm/s. part a what will the block's maximum speed be if its total energ

yKpoI14uk [10]

It will be 4 times of original thus maximum speed would be 80cm/s

6 0

3 years ago

Your washer has power of 450 watts, and your dryer has a power of 3000

qaws [65]

Answer:

See explanations below

Explanation:

Power = Workdone/Time

Power of washer = 450watts

Time used to clean the clothes = 1hour = 3600secs

Energy used to clean a load of clothes in 1 hour of

washing = 450/3600

Energy used to clean a load of clothes in 1 hour of

washing = 0.125Joules

For drying;

Energy = 3000/1.5*3600

Energy = 3000/5400

Energy = 0.556Joules

Hence the energy in washing id 0.556Joules

4 0

2 years ago

86 Km/h convertir a (m/min)

gogolik [260]

Answer: 1433.3 m/min

Explanation:

For 86 Km/h converted to a (m/min), convert kilometers to meters, and hour to minutes

So, 86 Km/h means 86 kilometers per 1 hour

- If 1 kilometer = 1000 metres

86 kilometers = 86 x 1000 = 86,000m

- If 1 hour = 60 minute

1 hour = 60 minutes

In m/min: (86,000m / 60 minute)

= 1433.3 m/min

Thus, 86 Km/h convert to 1433.3 m/min

5 0

3 years ago

An airplane has wings, each with area A, designed so that air flows over the top of the wing at 265 m/s and underneath the wing

exis [7]

Answer

given,

Pressure on the top wing = 265 m/s

speed of underneath wings = 234 m/s

mass of the airplane = 7.2 × 10³ kg

density of air = 1.29 kg/m³

using Bernoulli's equation

$P_1 + \dfrac{1}{2}\rho v_1^2 = P_2 + \dfrac{1}{2}\rho v_2^2$

$\Delta P =\dfrac{1}{2}\rho (v_2^2-v_1^2)$

$\Delta P =\dfrac{1}{2}\times 1.29\times (265^2-234^2)$

$\Delta P =9977.5 Pa$

Applying newtons second law

2 Δ P x A - mg = 0

$A =\dfrac{mg}{2\Delta P}$

$A =\dfrac{7.2\times 10^3 \times 9.8}{2\times 9977.5}$

A = 3.53 m²

7 0

3 years ago