Answer:
a) The schematic illustrating is attached
b) The heat transfer to the heat engine is 2142.86 kJ, the heat transfer from the heat engine is 1392.86 kJ
c) The heat transfer to the heat engine is 1648.35 kJ, the heat transfer from the heat engine is 898.35 kJ
Explanation:
b) The heat transfer to the engine and the heat transfer from the engine to the air is:
Where
W = 750 kJ
n = 35% = 0.25
Replacing:
c) The efficiency of Carnot engine is:
The heat transfer to the heat engine is:
The heat transfer from the heat engine is:
The answer is A) <span>The death rate begins to fall, but birth rates remain high for a time.</span>
Answer:
distance must be = 330 × 5/2
= 330×2.5
=825m
A contact force is a type of force which act on an object by coming in contact with the object. Examples of contact force that acts through a force field are: applied force, frictional force, air resistance force, tension, spring force, etc.
Examples of forces that act through a force field are gravitational force, electromagnetic force, the weak interaction and the strong interaction.
To solve this problem we will apply the concepts of energy conservation and Newton's second law that defines force as the product of the object's mass with its acceleration. Additionally we will apply concepts related to the kinematics equations of linear motion.
For conservation of energy we have that work is equal to kinetic energy therefore,
Here,
F = Force
d = Displacement
m = Mass
v= Velocity
At the same time we have the relation of
Therefore the value of the force can be interpreted as the rate of increase in energy per unit of distance, which makes it equivalent to
Applying Newton's Second Law
In 4 seconds final velocity of the object becomes
Then the work done is equal to,
Then the displacement is,
Therefore the distance moved is 16m
