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3 years ago

14

Evan drives a golf ball with an initial velocity of 49 meters per second at an angle of 16 degrees own a flat driving range. How

far will the golf ball land?

1 answer:

alexandr1967 [171]3 years ago

5 0

Answer:

<h2>solusion </h2><h2>Explanation:</h2><h2>the answer in 984 </h2>

tha

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Where does the USA get most of it's steel?

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China because it is cheaper then getting it from Pittsburgh

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3 years ago

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Work is a product of ___________.

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The correct option is D

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Which scenario does not describe an example of acceleration?

tekilochka [14]

Answer:

B is the right answer

Explanation:

It is decreasing.

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3 years ago

A 19 kg child is riding a 5.6 kg bike with a

icang [17]

Answer:

$\mathrm{a.\:}123\:\mathrm{kg\cdot m/s},\\\mathrm{b.\:}95\:\mathrm{kg\cdot m/s},\\\mathrm{c.\:}28\:\mathrm{kg\cdot m/s}$

Explanation:

The momentum of an object is given by:

$p=mv$ , where $m$ is the mass of the object and $v$ is the velocity of the object.

a)

The mass of the child and bike together is $19+5.6=24.6$ kilograms. Since they're moving at a velocity of 5.0 m/s, their momentum is:

$p=24.6\cdot 5=\fbox{$123\:\mathrm{kg\cdot m/s}$}$ .

b)

The mass of the child is given as 19 kg. Since the child is on the bike moving at 5.0 m/s, it's implied the child is as well. Therefore, the momentum of the child is:

$p=19\cdot 5=\fbox{$95\:\mathrm{kg\cdot m/s}$}$ .

c) The mass of the bike is given as 5.6 kg and it is moving at 5.0 m/s. Therefore, the momentum of the bike is:

<u /> $p=5.6\cdot 5=\fbox{$28\:\mathrm{kg\cdot m/s}$}$ <u />

4 0

3 years ago

A 310-km-long high-voltage transmission line 2.00 cm in diameter carries a steady current of 1,190 A. If the conductor is copper

Zolol [24]

Answer:

t = 141.55 years

Explanation:

As we know that the radius of the wire is

r = 2.00 cm

so crossectional area of the wire is given as

$A = \pi r^2$

$A = \pi(0.02)^2$

$A = 1.26 \times 10^{-3} m^2$

now we know the free charge density of wire as

$n = 8.50 \times 10^{28}$

so drift speed of the charge in wire is given as

$v_d = \frac{i}{neA}$

$v_d = \frac{1190}{(8.50 \times 10^{28})(1.6 \times 10^{-19})(1.26\times 10^{-3})}$

$v_d = 6.96 \times 10^{-5} m/s$

now the time taken to cover whole length of wire is given as

$t = \frac{L}{v_d}$

$t = \frac{310 \times 10^3}{6.96 \times 10^{-5}}$

$t = 4.46 \times 10^9 s$

$t = 141.55 years$

6 0

3 years ago