Answer:
a. 2.0secs
b. 20.4m
c. 4.0secs
d. 141.2m
e. 40m/s, ∅= -30°
Explanation:
The following Data are giving
Initial speed U=40m/s
angle of elevation,∅=30°
a. the expression for the time to attain the maximum height is expressed as
where g is the acceleration due to gravity, and the value is 9.81m/s if we substitute values we arrive at
b. the expression for the maximum height is expressed as
c. The time to hit the ground is the total time of flight which is twice the time to reach the maximum height ,
Hence T=2t
T=2*2.0
T=4.0secs
d. The range of the projectile is expressed as
e. The landing speed is the same as the initial projected speed but in opposite direction
Hence the landing speed is 40m/s at angle of -30°
Answer:
the aluminum would have the most mass
Given:
V1 = initial velocity = 24 m/s
a = acceleration = 2.0 m/s^2
s = time = 8 s
V2 = final velocity = ?
For linear-motion problems with those given terms, the following formula is used:
V2 = V1 + as
Substituting the given values:
V2 = 24 + 2(8)
V2 = 24 + 16
V2 = 40 m/s
Therefore the car will have a speed of 40 m/s as it leaves the tunnel.
<h2>
A N S W E R : –</h2>
Nothing happens to the brightness of the light bulbs in the parallel circuit if the power supply is capable of supplying the additional current.
Answer:
Explanation:
check attached image for figure, there is supposed to be a figure for this question containing a distance(height of collar at position A) but i will assume 0.2m or 200mm
Consider the energy equilibrium of the system
Here, F is the force acting on the collar, 
is the height of the collar at position A, m is the mass of the collar C, g is the acceleration due to gravity, 
is the velocity of the collar at position B, and 
is the velocity of the collar at A
Substitute 14.4N for F, 0.2m for , 1.5kg for m, 
for g and 0 for
Therefore, the velocity at which the collar strikes the end B is 4.412m/s
