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JulsSmile [24]
2 years ago
9

Shanti is riding on a train that is moving at a speed of 90 km/h. He is carrying a power cord for his phone that is 1.2 m long.

Physics
2 answers:
faltersainse [42]2 years ago
3 0

Answer:equal to 1.2 m

Explanation: i took the test

dalvyx [7]2 years ago
3 0

Answer:

D. equal to 1.2

Explanation:

on edg

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A solid, uniform disk of radius 0.250 m and mass 45.2 kg rolls down a ramp of length 5.40 m that makes an angle of 17.0° with th
serious [3.7K]

Explanation:

Given that,

Radius of the disk, r = 0.25 m

Mass, m = 45.2 kg

Length of the ramp, l = 5.4 m

Angle made by the ramp with horizontal, \theta=17^{\circ}

Solution,

As the disk starts from rest from the top of the ramp, the potential energy is equal to the sum of translational kinetic energy and the rotational kinetic energy or by using the law of conservation of energy as :

(a) mgh=\dfrac{1}{2}mv^2+\dfrac{1}{2}I\omega^2

h is the height of the ramp

sin\theta=\dfrac{h}{5.4}

h=sin(17)\times 5.4=1.57\ m

v is the speed of the disk's center

I is the moment of inertia of the disk,

I=\dfrac{1}{2}mr^2

\omega=\dfrac{v}{r}

mgh=\dfrac{1}{2}mv^2+\dfrac{1}{2}\dfrac{1}{2}mr^2\times (\dfrac{v}{r})^2

gh=\dfrac{1}{2}v^2+\dfrac{1}{4}v^2

gh=\dfrac{3}{4}v^2

9.8\times 1.57=\dfrac{3}{4}v^2

v = 4.52 m/s

(b) At the bottom of the ramp, the angular speed of the disk is given by :

\omega=\dfrac{v}{r}

\omega=\dfrac{4.52}{0.25}

\omega=18.08\ rad/s

Hence, this is the required solution.

4 0
3 years ago
Which statements describe how chemical formulas, such as H2O, represent compounds? Check all that apply.
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The statements that apply in this case are:

They show the elements that make up a compound.

They show the types of atoms that make up a molecule.

They show the number of each type of atom in a molecule.

5 0
3 years ago
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(PLEASE HELP) What area of the Earth's mantle is the densest?
Nady [450]
The area nearest to the earth's core is the densest.. 
So your answer would be letter choice ( D ) . . . 

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3 years ago
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Consider 2 converging lenses of focal lengths 5 mm (objective) and 50 mm.(eyepiece) An object 0.1 mm in size is placed a distanc
AleksandrR [38]

Answer:

1)   q₁ = 12.987 cm , b)       L = 17.987 cm , c)      m = 179.87

Explanation:

We can solve the geometric optics exercises with the equation of the constructor

         1 / f = 1 / p + 1 / q

where f is the focal length, p and q are the distance to the object and the image respectively.

Let's apply this equation to our case

1) f = 5mm = 0.5 cm

    p₁ = 5.2 mm = 0.52 cm

    h = 0.1 mm = 0.01 cm

    1 / q₁ = 1 / f- 1 / p

    1 / q₁ = 1 / 0.5 - 1 / 0.52 = 2 - 1.923

    1 / q₁ = 0.077

    q₁ = 12.987 cm

2) in this part they tell us that the eyepiece creates an image at infinity, therefore the object that comes from being at the focal length of the eyepiece

            p₂ = 5 cm

The absolute thing that goes through the two lenses is

           L = q₁ + p₂

           L = 12.987 +5

           L = 17.987 cm

3) This lens configuration forms the so-called microscope, whose expression for the magnifications

           m = -L / f_target 25 cm / f_ocular

           m = - 17.987 / 0.5 25 / 5.0

            m = 179.87

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2 years ago
What is motion and how do we determine it
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