Explanation:
In my view, when the Object A is attracted to a Charged object B. Object B should be Negatively or Positively charged. So Object B should be the Opposite charged according to the Object B
Example =
If Object B is Negatively Charged, the Object A should be Positively Charged
If the Object B is Positively Charged, the Object A should be Negatively Charged
Sometimes it can Mix as a Neutral as well
Hope this Helps
An unconformity, or abnormality in the layers of rocks, signifies that the process of layering was somehow interrupted. The only feasible choice for this would be (B), where erosion would have interrupted the layering process.
Answer:
Weight needed to balance the bar is 
Explanation:
Given the weight of the bar is 
The length of the bar is 
The weight of the bar will be uniformly distributed over the entire span. We will consider this as a point load acting in the middle of span length, which is at a distance of
from both ends.
Now applying momentum equation about balanced load we get, (see attachment)

Explanation:
1. The kinetic energy of any object is calculated as :
...........(1)
Dimensional formula of energy, ![[E]=[ML^2T^{-2}]](https://tex.z-dn.net/?f=%5BE%5D%3D%5BML%5E2T%5E%7B-2%7D%5D)
Dimensional formula of mass is ![[M]](https://tex.z-dn.net/?f=%5BM%5D)
Dimensional formula of velocity, ![[v]=[LT^{-1}]](https://tex.z-dn.net/?f=%5Bv%5D%3D%5BLT%5E%7B-1%7D%5D)
![[ML^2T^{-2}]=\dfrac{1}{2}[M]([LT^{-1}])^2](https://tex.z-dn.net/?f=%5BML%5E2T%5E%7B-2%7D%5D%3D%5Cdfrac%7B1%7D%7B2%7D%5BM%5D%28%5BLT%5E%7B-1%7D%5D%29%5E2)
So, ![[ML^2T^{-2}]=[ML^2T^{-2}]](https://tex.z-dn.net/?f=%5BML%5E2T%5E%7B-2%7D%5D%3D%5BML%5E2T%5E%7B-2%7D%5D)
LHS = RHS
2. The potential energy is given by :

Dimensional formula of mass is ![[M]](https://tex.z-dn.net/?f=%5BM%5D)
Dimensional formula of g is ![[LT^{-2}]](https://tex.z-dn.net/?f=%5BLT%5E%7B-2%7D%5D)
Dimensional formula of height is ![[L]](https://tex.z-dn.net/?f=%5BL%5D)
Dimensional formula of energy, ![[E]=[ML^2T^{-2}]](https://tex.z-dn.net/?f=%5BE%5D%3D%5BML%5E2T%5E%7B-2%7D%5D)
So, ![E=[M][LT^{-2}][L]](https://tex.z-dn.net/?f=E%3D%5BM%5D%5BLT%5E%7B-2%7D%5D%5BL%5D)
So, LHS = RHS
Hence, this is the required solution.