Answer:
69.8%
Explanation:
k = 0.00813 sec-1
t = 44.1 s
What percentage of the compound has decomposed?
We can obtain this using the formular;
[A] = [A]o e^(-kt)
where;
Final Concentration = [A]
Initial concentration = [A]o
[A] / [A]o = e^(-kt)
[A] / [A]o = e^(-0.00813*44.1)
[A] / [A]o = e^(-0.359)
[A] / [A]o = 0.698
Percentage decomposed = Final Concentration / Initial concentration * 100
Percentage decomposed = [A] / [A]o * 100%
Percentage decomposed = 0.698 * 100 = 69.8%
Answer:
The answer is Oxygen
The oxygen has the most electronegativity.
Answer:
C) before you start your job
Explanation:
its the 1st thing to do when ur on a job...i guess not sure but try it anyway....but if im wrong blame
I'm not quiet sure...possibly an ionic bond.
Answer:
1.18 moles of CS₂ are produced by the reaction.
Explanation:
We present the reaction:
5C + 2SO₂ → CS₂ + 4CO
5 moles of carbon react to 2 moles of sulfur dioxide in order to produce 1 mol of carbon disulfide and 4 moles of carbon monoxide.
As we do not have data from the SO₂, we assume this as the excess reagent. We convert the mass of carbon to moles:
70.8 g / 12 g/mol = 5.9 moles
Ratio is 5:1, so 5 moles of carbon react to produce 1 mol of CS₂
Then, 5.9 moles will produce (5.9 . 1) / 5 = 1.18 moles