Answer:
Vapor pressure for solution is 22.4 Torr
Explanation:
P° → Vapor pressure of pure solvent
P' → Vapor pressure of solution
Formula for lowering vapor pressure is: P° - P' = P° . Xm
Xm is the mole fraction. Let's determine it:
0.220 mol of solute + 3.70 mol of water = 3.92 total moles
Mole fraction for solute → 0.220 / 3.92 = 0.056
23.8 Torr - P' = 23.8 Torr . 0.056
P' = - ( 23.8 Torr . 0.056 - 23.8 Torr ) → 22.4 Torr
Answer:
24.7 grams H₂O
Explanation:
To find the mass of water, you should (1) convert from grams HCl to moles (via molar mass from periodic table), then (2) convert from moles HCl to moles H₂O (via mole-to-mole ratio from equation), and then (3) convert from moles H₂O to grams (via molar mass from periodic table).
1 HCl + KOH --> 1 H₂O + KCl
Molar Mass (HCl): 1.008 g/mol + 35.45 g/mol
Molar Mass (HCl): 36.458 g/mol
Molar Mass (H₂O): 2(1.008 g/mol) + 16.00 g/mol
Molar Mass (H₂O): 18.016 g/mol
50 g HCl 1 mole HCl 1 mole H₂O 18.016 g
-------------- x ------------------ x ------------------- x ------------------- = 24.7 g H₂O
36.458 g 1 mole HCl 1 mole H₂O
Answer: When an acidic solution is diluted with water the concentration of H + ions decreases and the pH of the solution increases towards 7.
Explanation:
175.8 g NaCl to moles:
(175.8 g)/(58.44 g/mol) = 3.008 mol NaCl
Molarity = moles of solute/volume of solution in liters
(3.008 mol NaCl)/(1.5 L) = 2.0 M.
The molarity of this solution would be 2.0 M.
