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Korolek [52]
3 years ago
15

A 2,000g of C-14 is left to decay radioactively. The half-life of Carbon-14 is approximately 5,700 years. What percentage of the

sample will remain after 17,100 years?
Chemistry
2 answers:
dsp733 years ago
4 0
Answer is: 12,6% (1/8) <span>percentage of the sample will remain.
</span>c₀ - initial amount of C-14.<span>
c - amount of C-14 remaining at time.
t = 5700</span> y.<span>
First calculate the radioactive decay rate constant λ:
λ = 0,693 ÷ t = 0,693 ÷ 5700</span> y = 0,000121 1/y = 1,21·10⁻⁴ y.
c = c₀·e∧-λ·t.
c = 2000 · e∧-(0,000121 1/y · 17100 y).
c = 252 g.
ω = 252 g ÷ 2000 g = 0,126 = 12,6%.
<span>

</span>
mart [117]3 years ago
3 0

1/8 when using usatestprep

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What change in volume results if 50 mL of gas is cooled from 30 C to 4 C
11111nata11111 [884]

The relation between the volume of the gas and the temperature is established by Charles's law. With a decrease in the temperature, the volume decreases by 45.7 mL. Thus, option c is correct.

<h3>What is Charle's law?</h3>

Charle's law states the direct relation present between the temperature and the volume of the gas. The law is given as:

V₁ ÷ T₁ = V₂ ÷ T₂

Given,

V₁ = 50 mL

T₁ = 303.15 K

T₂ = 277.15 K

Substituting the value the final volume is calculated as:

50 ÷ 303.15 = V₂ ÷ 277.15

V₂ = (50 × 277.15) ÷ 303.15

= 45.71 mL

Therefore, option c. 45.7 mL is the final volume.

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5 0
2 years ago
In Philip’s French class, the students are learning how to pronounce closed vowels and open vowels. The students are most likely
Sladkaya [172]

Answer:

It sounds like they are studying French phonemes

Explanations:

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7 0
3 years ago
Read 2 more answers
What is the density of aluminum in grams per cubic centimeter?
oksano4ka [1.4K]

Answer:

Density of aluminum is 2.699 g/cm^3

Explanation:

Density of a given material can be defined as the mass of the substance present in a unit volume. Mathematically it can be expressed as:

Density = \frac{Mass}{Volume}

Units: g/cm^3 or kg/m^3

Aluminum (Al) is one the lightest element and is known to have a density of 2.699 g/cm^3

5 0
2 years ago
Determine the empirical formula of the following compound if a sample contains 0.104 molK, 0.052 molC, and 0.156 molO;?
faltersainse [42]

Answer:

K₂CO₃    

Explanation:

Given parameters:

Number of moles of K = 0.104mol

Number of moles of C = 0.052mol

Number of moles of O = 0.156mol

Method

From the given parameters, to calculate the empirical formula of the elements K, C and O, we reduce the given moles to the simplest fraction.

Empirical formula is the simplest formula of a compound and it differs from the molecular formula which is the actual formula of a compound.

  • Divide the given moles through by the smallest which is C, 0.052mol.
  • Then approximate values obtained to the nearest whole number of multiply by a factor to give a whole number ratio.
  • This is the empirical formula

Solution

Elements                             K                       C                    O

Number of moles            0.104                0.052            0.156

Dividing by the

smallest                       0.104/0.052     0.052/0.052  0.156/0.052

                                            2                           1                     3

The empirical formula is K₂CO₃      

3 0
2 years ago
Construct a simulated 1H NMR spectrum for ethyl acetate by dragging and dropping the appropriate splitting patterns into the box
Ksju [112]

Answer:

The simulated 1H NMR spectrum for ethyl acetate is shown in the drawing attached.

Explanation:

To construct this NMR it is necessary to identify the essential components that can produce resonance peaks.

Two main groups can be identified, the acetyl group containing a sub-component (CH3) capable of producing a resonance peak, and the ethyl group containing two components (CH2 and CH3) each of which can produce on its own its own resonance peak.

6 0
3 years ago
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