A substance has a triple point at −24.5 ∘C and 225 mmHg. What is most likely to happen to a solid sample of the substance as it
is warmed from −35 ∘C to 5 ∘C at a pressure of 210 mmHg?Nothing (the solid will remain as a solid).The solid will sublime into a gas.The solid will melt into a liquid.
1 answer:
Answer:
The solid will sublime into a gas
Explanation:
In the graph in the attachment
Y-axis represents pressure in mm of Hg
X- axis represents temperature in degree Celsius
The graph show the triple point of water.
Clearly, the sample will go from solid to vapor directly, no liquid involved (pink line is there to show that this is below triple point)
So
expect sublimation
The solid will sublime into a gas.
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Answer:
The four resonance structures of the phenoxide ion are shown in the image attached
The conjugate base of cyclohexanol has only one resonance contributor, while
the conjugate base of phenol has four resonance contributors.
Explanation:
In organic chemistry, it is known that structures are more stable if they possess more resonance contributors. The greater the number of contributing canonical structures, the more stable the organic specie. Since the phenoxide ion has four contributing canonical structures, it is quite much more stable than cyclohexanol having only one contributing structure to its conjugate base. Hence the PKa(acid dissociation constant) of phenol is lesser than that of cyclohexanol. The conjugate base of phenol is stabilized by resonance.
