A substance has a triple point at −24.5 ∘C and 225 mmHg. What is most likely to happen to a solid sample of the substance as it
is warmed from −35 ∘C to 5 ∘C at a pressure of 210 mmHg?Nothing (the solid will remain as a solid).The solid will sublime into a gas.The solid will melt into a liquid.
1 answer:
Answer:
The solid will sublime into a gas
Explanation:
In the graph in the attachment
Y-axis represents pressure in mm of Hg
X- axis represents temperature in degree Celsius
The graph show the triple point of water.
Clearly, the sample will go from solid to vapor directly, no liquid involved (pink line is there to show that this is below triple point)
So
expect sublimation
The solid will sublime into a gas.
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Answer:
(A) 0.129 M
(B) 0.237 M
Explanation:
(A) The reaction between potassium hydrogen phthalate and barium hydroxide is:
- 2HA + Ba(OH)₂ → BaA₂ + 2H₂O
Where A⁻ is the respective anion of the monoprotic acid (KC₈H₄O₄⁻).
We <u>convert mass of phthalate to moles</u>, using its molar mass:
- 0.978 g ÷ 156 g/mol = 9.27x10⁻³ mol = 9.27 mmol
Now we <u>convert mmol of HA to mmol of Ba(OH)₂</u>:
- 9.27 mmol HA *
= 6.64 mmol Ba(OH)₂
Finally we calculate the molarity of the Ba(OH)₂ solution:
- 6.64 mmol / 35.8 mL = 0.129 M
(B) The reaction between Ba(OH)₂ and HCl is:
- 2HCl + Ba(OH)₂ → BaCl₂ + 2H₂O
So<u> the moles of HCl that reacted </u>are:
- 17.1 mL * 0.129 M *
= 4.41 mmol HCl
And the <u>molarity of the HCl solution is</u>:
- 4.41 mmol / 18.6 mL = 0.237 M