The third one
synthesis reactions have multiple reactants that synthesize into one product
The answer is strong winds
Answer : The excess reactant in the combustion of methane in opem atmosphere is
molecule.
Solution : Given,
Mass of methane = 23 g
Molar mass of methane = 16.04 g/mole
The Net balanced chemical reaction for combustion of methane is,

First we have to calculate the moles of methane.
=
= 1.434 moles
From the above chemical reaction, we conclude that
1 mole of methane react with the 2 moles of oxygen
and 1.434 moles of methane react to give
moles of oxygen
The Moles of oxygen = 2.868 moles
Now we conclude that the moles of oxygen are more than the moles of methane.
Therefore, the excess reactant in the combustion of methane in open atmosphere is
molecule.
Answer:
632.32 mmHg
Explanation:
Millimetre mercury:
It is the monometric unit of pressure. It is define as "The pressure exerted by the column pf mercury at the height of 1 millimetre.
It is represented as mmHg.
It can also be written as mm Hg.
Atmosphere (atm):
It is barometric pressure, define as "The force exerted by atmospheric column on per unit area".
It is written as "atm".
Conversion of atm to mmHg:
0.832 atm × 760 mmHg / 1 atm
632.32 mmHg
Answer:
12,742 km
Explanation:
Therefore, its radius is 6,371 km.