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3 years ago

If all else stays the same, which would cause an increase in the gravitational force on a space shuttle?

Physics

2 answers:

Alenkasestr [34]3 years ago

8 0

Answer: Decreasing the distance of the space shuttle from Earth .

Explanation:

According to expression of gravitational force:

$F=\frac{G\times m_1\times m_2}{r^2}$

G = gravitational constant

$m_1, m_2$ = masses of two objects

r = Distance between the two objects.

F = Gravitational force

From the above expression we can say that gravitational force is inversely proportional to squared of the distance between the two masses.

$F\propto \frac{1}{r^2}$

So, in order to increase the gravitational force on space shuttle distance between the space space shuttle must be decreased.

Hence, the correct answer 'decreasing the distance of the space shuttle from Earth '.

Troyanec [42]3 years ago

8 0

Answer:

The correct answer is B.

Explanation:

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Near the center of our galaxy, hydrogen gas is moving directly away from us in its orbit about a black hole. The electromagnetic

Aleonysh [2.5K]

Answer:

The speed of the gas relative to the earth = 6.314 * $10^{6} m/s$

Explanation:

Let the observed wavelength be $\lambda_{0} = 1915 nm$

The wavelength of the source, $\lambda_{s} = 1875 nm$

Let the speed of the gas relative to the earth be = v

The observed wavelength in relation to the source wavelength, according to doppler shift in relativity can be expressed as:

$\lambda_{0} = \lambda_{s}\sqrt{\frac{1-\frac{v}{c} }{1+\frac{v}{c} } }$

Where the speed of light, c = 3 * 10⁸m/s

$\frac{\lambda_{0}}{\lambda_{s}} = \sqrt{\frac{1-\frac{v}{c} }{1+\frac{v}{c} } }\\(\frac{\lambda_{0}}{\lambda_{s}})^{2} = \frac{1-\frac{v}{c} }{1+\frac{v}{c} }\\(\frac{1915}{1875}) ^{2}( {1+\frac{v}{c}) = ({1-\frac{v}{c} }) \\$

$1.043 +\frac{1.043v}{c} = 1 - \frac{v}{c} \\\frac{1.043v}{c} + \frac{v}{c} = 1-1.043\\2.043v = -0.043c\\v = \frac{-0.043c}{2.043} \\v = -0.02105c\\v = -0.02105 * 3 * 10^{8} \\v = -6314243.76 m/s\\The absolute value, v = 6314243.76 m/s\\v = 6.314 * 10^{6} m/s$

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3 years ago

Which of the following objects has no kinetic energy ?

Elena-2011 [213]

Answer:

delivery truck

Explanation:

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3 years ago

Gauss’s law applies to:_____________

stich3 [128]

Answer:

D. Closed Surfaces

The gaussian surface could be a sphere and can be applied to flat surfaces, but it's always a closed surface.

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4 years ago

A car traveling 77 km/h slows down at a constant 0.48 m/s2 just by "letting up on the gas." A) Calculate the distance the car co

vfiekz [6]

Answer:

(a) 477 m

(b) 44.6 s

(d) 19.24 m

Explanation:

initial speed, u = 77km/h = 21.4 m/s

acceleration, a = - 0.48 m/s2

final speed v = 0

(a) let the stopping distance is s.

Use third equation of motion

$v^2 = u^2 + 2 a s\\\\0 = 21.4^2 - 2 \times 0.48\times s\\\\s = 477 m$

(b) Let t is time.

Use first equation of motion

v = u + at

0 = 21.4 - 0.48 t

t = 44.6 s

Use second equation of motion

$s = u t + 0.5 at^2\\\\s = 21.4\times 1 - 0.5\times 0.48\times 1\\\\s = 21.4 - 0.24 = 21.16 m$

(d) distance traveled in 5 th second is given by

$s = u + 0.5 a (2 n - 1) \\\\s = 21.4 - 0.5\times 0.48 \times (2\times 5 -1)\\\\s= 21.4 - 2.16 = 19.24 m$

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3 years ago

Usually, large amount of curent flows in a<br> Circuit due to two reasons ———— and ————.

omeli [17]

Answer:

Explanation:

Possible causes for overcurrent include short circuits, excessive load, incorrect design, an arc fault, or a ground fault. Fuses, circuit breakers, and current limiters are commonly used overcurrent protection (OCP) mechanisms to control the risks

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3 years ago