A positively charged light metal ball is suspended between two oppositely charged metal plates on an insulating thread as shown
1 answer:
You might be interested in
The characteristics of thermal expansion allow finding that the response for a material without thermal expansion is
- The length variation is zero
- In the graph the line is horizontal so there is no change in length with temperature
Thermal expansion is the macroscopic sum of the changes in the length of the bonds when the energy (temperature) changes, it can be written
ΔL = α L₀ ΔT
Where ΔL is the change in length, α the coefficient of linear expansion, L₀ the initial length and ΔT the change in body temperature
In this case, a material is being designed that the thermal expansion is very small, for this the material must be made up of several compounds where some of them present a contraction with temperature, some examples: water at low temperature, liquefied gases , ceramic tile, quartz, etc.
The thermal expansion measurement processes control the body temperature and measure the change in length, in this case the change in length must be zero, in the attachment we can see a graph of a composite material with these characteristics, an example of this type of material is Invar an alloy of nickel and iron α = 3.7 10⁻⁶ ºC⁻¹
In conclusion, using the characteristics of thermal expansion we can find that the response of material without thermal expansion is
- The length variation is zero
- In the graph the line is horizontal so there is no change in length with temperature
Learn more here: brainly.com/question/18717902
The question is incomplete. Here is the complete question.
To understand the decibel scale. The decibel scale is a logarithmic scale for measuring the sound intensity level. Because the decibel scale is logarithmic, it changes by an additive constant when the intensity when the intensity as measured in W/m² changes by a multiplicative factor. The number of decibels increase by 10 for a factor of 10 increase in intensity. The general formula for the sound intensity level, in decibels, corresponding to intensity I is
,
where is a reference intensity. for sound waves,
is taken to be
. Note that log refers to the logarithm to the base 10.
Part A: What is the sound intensity level β, in decibels, of a sound wave whose intensity is 10 times the reference intensity, i.e. ? Express the sound intensity numerically to the nearest integer.
Part B: What is the sound intensity level β, in decibels, of a sound wave whose intensity is 100 times the reference intensity, i.e. ? Express the sound intensity numerically to the nearest integer.
Part C: Calculate the change in decibels ( and
) corresponding to f = 2, f = 4 and f = 8. Give your answer, separated by commas, to the nearest integer -- this will give an accuracy of 20%, which is good enough for sound.
Answer and Explanation: Using the formula for sound intensity level:
A)
β = 10
<u>The sound Intensity level with intensity 10x is </u><u>10dB</u>.
B)
β = 20
<u>With intensity 100x, level is </u><u>20dB</u>.
C) To calculate the change, take the f to be the factor of increase:
For :
β = 3
For :
β = 6
For :
β = 9
Change is
,
= 3,6,9 dB