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Savatey [412]
3 years ago
12

A positively charged light metal ball is suspended between two oppositely charged metal plates on an insulating thread as shown

below. After being charged once, the plates are disconnected from the battery. Describe the behavior of the ball. Please use 3 content related sentences. (
Physics
1 answer:
Tcecarenko [31]3 years ago
6 0

Answer:

The positive ball would go first to the negatively charged plate.

Explanation:

After which, it would hold a more negative charge. Due to the negative charge, it would travel towards the positive plate. Thereby, it would transfer negative electrons to the positive plate once more. In doing so, it would transfer positive protons to the negative plate. After which, it would hold more  negative electrons and be drawn towards the positive plate once more. The Process would continue until the once-positive and once-negative became neutral ( and were discharged.) Additionally, the ball hanging on the insulator thread would also be neutral and discharged.

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There's an electric field in some region of space that doesn't change with position. An electron starts moving with a speed of 2
tangare [24]

Answer:

Explanation:

Given

speed of Electron u=2\times 10^7\ m/s

final speed of Electron v=4\times 10^7\ m/s

distance traveled d=1.2\ cm

using equation of motion

v^2-u^2=2as

where v=Final velocity

u=initial velocity

a=acceleration

s=displacement

(4\times 10^7)^2-(2\times 10^7)^2=2\times a\times 1.2\times 10^{-2}

a=5\times 10^{16}\ m/s^2

acceleration is given by a=\frac{qE}{m}

where q=charge of electron

m=mass of electron

E=electric Field strength

5\times 10^{16}=\frac{1.6\times 10^{-19}\cdot E}{9.1\times 10^{-31}}

E=248.3\ kN/C                

5 0
3 years ago
What was the main view how the world worked geologically prior to the 1960s? It was generally believed that continents and ocean
attashe74 [19]

Answer:

It was generally believed that mountains were produced by vertical forces

Explanation:

                   The main view of the world worked geologically prior to the 1960s was that the mountains were formed by the vertical forces of nature.

                    The early people prior to 1960s believed in many different natural phenomenons and they give their own reasons for their occurrence. But later many researchers and geophysicists studied the formation of the earth and came with possible answers to these questions.

Thus the answer is  

" It was generally believed that mountains were produced by vertical forces."

3 0
3 years ago
A jet is circling an airport control tower at a distance of 20.6 km. An observer in the tower watches the jet cross in front of
lesya [120]

Answer:

197.76 m

Explanation:

r = Radius of the path = 20.6 km = 20.6\times 10^3\ m

\theta = The angle subtended by moon = 9.6\times 10^{-3}\ rad

Distance traveled is given by

s=r\times\theta

\Rightarrow s=20.6\times 10^3\times 9.6\times 10^{-3}

\Rightarrow s=197.76\ m

The distance traveled by the jet is 197.76 m

8 0
3 years ago
A 7600 kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.35 m/s2 and feels no appreci
ollegr [7]

Answer:

a) The rocket reaches a maximum height of 737.577 meters.

b) The rocket will come crashing down approximately 17.655 seconds after engine failure.

Explanation:

a) Let suppose that rocket accelerates uniformly in the two stages. First, rocket is accelerates due to engine and second, it is decelerated by gravity.

1st Stage - Engine

Given that initial velocity, acceleration and travelled distance are known, we determine final velocity (v), measured in meters per second, by using this kinematic equation:

v = \sqrt{v_{o}^{2} +2\cdot a\cdot \Delta s} (1)

Where:

a - Acceleration, measured in meters per square second.

\Delta s - Travelled distance, measured in meters.

v_{o} - Initial velocity, measured in meters per second.

If we know that v_{o} = 0\,\frac{m}{s}, a = 2.35\,\frac{m}{s^{2}} and \Delta s = 595\,m, the final velocity of the rocket is:

v = \sqrt{\left(0\,\frac{m}{s} \right)^{2}+2\cdot \left(2.35\,\frac{m}{s^{2}} \right)\cdot (595\,m)}

v\approx 52.882\,\frac{m}{s}

The time associated with this launch (t), measured in seconds, is:

t = \frac{v-v_{o}}{a}

t = \frac{52.882\,\frac{m}{s}-0\,\frac{m}{s}}{2.35\,\frac{m}{s} }

t = 22.503\,s

2nd Stage - Gravity

The rocket reaches its maximum height when final velocity is zero:

v^{2} = v_{o}^{2} + 2\cdot a\cdot (s-s_{o}) (2)

Where:

v_{o} - Initial speed, measured in meters per second.

v - Final speed, measured in meters per second.

a - Gravitational acceleration, measured in meters per square second.

s_{o} - Initial height, measured in meters.

s - Final height, measured in meters.

If we know that v_{o} = 52.882\,\frac{m}{s}, v = 0\,\frac{m}{s}, a = -9.807\,\frac{m}{s^{2}} and s_{o} = 595\,m, then the maximum height reached by the rocket is:

v^{2} -v_{o}^{2} = 2\cdot a\cdot (s-s_{o})

s-s_{o} = \frac{v^{2}-v_{o}^{2}}{2\cdot a}

s = s_{o} + \frac{v^{2}-v_{o}^{2}}{2\cdot a}

s = 595\,m + \frac{\left(0\,\frac{m}{s} \right)^{2}-\left(52.882\,\frac{m}{s} \right)^{2}}{2\cdot \left(-9.807\,\frac{m}{s^{2}} \right)}

s = 737.577\,m

The rocket reaches a maximum height of 737.577 meters.

b) The time needed for the rocket to crash down to the launch pad is determined by the following kinematic equation:

s = s_{o} + v_{o}\cdot t +\frac{1}{2}\cdot a \cdot t^{2} (2)

Where:

s_{o} - Initial height, measured in meters.

s - Final height, measured in meters.

v_{o} - Initial speed, measured in meters per second.

a - Gravitational acceleration, measured in meters per square second.

t - Time, measured in seconds.

If we know that s_{o} = 595\,m, v_{o} = 52.882\,\frac{m}{s}, s = 0\,m and a = -9.807\,\frac{m}{s^{2}}, then the time needed by the rocket is:

0\,m = 595\,m + \left(52.882\,\frac{m}{s} \right)\cdot t + \frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right)\cdot t^{2}

-4.904\cdot t^{2}+52.882\cdot t +595 = 0

Then, we solve this polynomial by Quadratic Formula:

t_{1}\approx 17.655\,s, t_{2} \approx -6.872\,s

Only the first root is solution that is physically reasonable. Hence, the rocket will come crashing down approximately 17.655 seconds after engine failure.

7 0
3 years ago
A battery supplies ________ to the circuit.
MariettaO [177]

Answer:

Electrical energy

Explanation:

<em>Hope </em><em>It </em><em>helps </em><em>you </em>

6 0
2 years ago
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