Ask question

Ask question

All categories

2 years ago

13

An object with a mass of m = 122 kg is suspended by a rope from the end of a uniform boom with a mass of M = 74.9 kg and a lengt

h of l = 8.77 m. The end of the boom is supported by another rope which is horizontal and attached to the wall as shown in the figure.
1. Calculate the tension in the horizontal rope. (The horizontal and the vertical ropes are not connected to each other. They are both independently attached to the end of the boom.)

1 answer:

creativ13 [48]2 years ago

7 0

The horizontal rope is under 7,019.4 N of tension.

The pulling force conveyed axially by a string, cable, chain, or another similar device, or by the ends of a rod, is referred to as tension.

The action-reaction pair of forces acting at the ends of the element can also be referred to as tension.

The tension unit is the Newton.

the horizontal rope is tense.

The following formula is used to determine the horizontal rope's tension:

Apply the torque principle;

Mg (L/2) sin + mg L sin = T(L/2) cos

M + 2mg sin/cos = T

(M + 2m)g tan = T

let θ = 66⁰ (The question should include this value)

(M + 2m)g tan = T

T = (74.9 + 2 x 122)(9.8) (tan 66)

T = 7,019.4 N

7,019.4 N is the tension in the horizontal rope.

Learn more about tension here: brainly.com/question/918617

#SPJ1

You might be interested in

Explain how longitudinal waves and transverse waves are similar to each other and different from each other.

VashaNatasha [74]

Similar:
-
For transverse waves, the waves move in perpendicular direction to the source of vibration.
For longitudinal waves, the waves move in parallel direction to the source of vibration .
They are similar in the sense that energy is transferred in the form of waves.
-
Difference:
-
Transverse Waves: Displacement of the medium is perpendicular to the direction of propagation of the wave.
Longitudinal Waves: Displacement of the medium is parallel to the direction of propagation of the wave.

3 0

3 years ago

What velocity will a freefalling object have after falling 80 meters

vovangra [49]

Answer:

129.96

At a Gravitational acceleration of 32.17405 ( which is the normal rate for a freefall) you will geta velocity of 129.96 and the time of fall will be 4.039 seconds from 80 meters.

Why is the weight of a free falling body zero? It is not, an object in free fall will still have a weight, governed by the equation W = mg, where W is the object's weight, m is the object's mass, and g is acceleration due to gravity. Weight, however, has no effect on an objects free falling speed, two identically shaped objects weighing a different amount will hit the ground at the same time.

Hope this helps!! If so please mark brainliest and rate/heart to help my account if it did!!

6 0

3 years ago

Plz guys I again need help

lara [203]

Answer:

idk

Explanation:

7 0

4 years ago

Read 2 more answers

In order to catch a fast-moving softball with your bare hand, you extend your hand forward just before the catch and then let th

hichkok12 [17]

This is a concept of momentum. In equation, momentum is the product of force and distance. When a ball is thrown, its force is constant all throughout unless disturbed by an external force. Therefore, force is the constant of proportionality that relates momentum with distance. When you block a ball from a given distance, you would feel the great force on your hand. In order to reduce the force, you have to follow the direction of the force in order to minimize the impact. By doing this, you gradually decrease the momentum of the ball.

8 0

3 years ago

A solenoid that is 66.1 cm long has a cross-sectional area of 13.8 cm2. There are 1410 turns of wire carrying a current of 8.01

Ymorist [56]

Answer:

a) Energy density of the magnetic field, u = 183.46 J/m³

b) Total energy, E = 0.167 J

Explanation:

a) Number of turns in the solenoid, N = 1410

Area, A = 13.8 cm² = 0.00138 m²

Current, I = 8.01 A

Length of the solenoid, l = 66.1 cm = 0.661 m

Energy density, u is given by the formula $u = \frac{B^2}{2 \mu_{0} }$

Where B is the magnetic field

The magnetic field in a solenoid is given by the formula, $B = \frac{N \mu_{0} I }{l}$

$B = \frac{1410 * 8.01* \mu_{0} }{0.661}$

$B = 17086.38 \mu_0$ T

$u = \frac{(17086.38 \mu_0)^2}{2 \mu_{0} }\\u = \frac{291944527.29 \mu_0^2}{2 \mu_{0} }\\u = \frac{291944527.29 \mu_0}{2 }\\u = \frac{291944527.29 * 4\pi * 10^{-7} }{2 }\\u = 183.46 J/m^3$

b) The total energy = Energy density * Volume

E = u V

Volume = Area * Length

V = Al = 0.00138 * 0.661

V = 0.00091218 m³

E = 183.46 * 0.00091218

E = 0.167 J

4 0

3 years ago