-- When the 7.1 and 12.6 sides both point in exactly the same direction,
their open ends are 5.5 apart. So the missing side must be greater than 5.5 .
All of the choices are greater than 5.5 , so we haven't found it yet.
-- When the 7.1 and 12.6 point in opposite directions, their open ends are
19.7 apart. So the missing side can't be greater than 19.7, otherwise the
two sides we know couldn't reach between its ends. <u>Choice 'E'</u> is greater
than 19.9, so it can't be the missing side.
Answer: 13 . 99 seconds
Step-by-step explanation:
The formula to find how long it will take an object to rotate through 6.9 revolutions at an angular velocity is given as :
t = 2π x number of revolutions / angular velocity
Therefore :
t = 2π x 6.9 / 3.1
t = 2 x 3.142 x 6.9 / 3.1
t = 43.3596/3.1
t = 13. 98696774194
to the nearest tenth
t = 13. 99s
The answer is -40 because if you get rid of the negative sign and add instead of subtract... you get 40 so its like adding in the opposite direction.
Answer: a) H = h( 0.5 )^n
b) H = 1.125inches
Step-by-step explanation:
Let H = height of the ball
n = number of time the ball bounces
h = initial height.
The exponential function to model the height of the ball will be:
H = h( 1 - 0.5)^n
H = h( 0.5 )^n
It's minus because the height of the ball is decreasing.
h = 36 inches
n = 5
H = 36( 1 - 0.5 ) ^5
H = 36( 0.5 )^5
H = 36 × 0.03125
H = 1.125inches
<h3>Refer to the diagram below</h3>
- Draw one smaller circle inside another larger circle. Make sure the circle's edges do not touch in any way. Based on this diagram, you can see that any tangent of the smaller circle cannot possibly intersect the larger circle at exactly one location (hence that inner circle tangent cannot be a tangent to the larger circle). So that's why there are no common tangents in this situation.
- Start with the drawing made in problem 1. Move the smaller circle so that it's now touching the larger circle at exactly one point. Make sure the smaller circle is completely inside the larger one. They both share a common point of tangency and therefore share a common single tangent line.
- Start with the drawing made for problem 2. Move the smaller circle so that it's partially outside the larger circle. This will allow for two different common tangents to form.
- Start with the drawing made for problem 3. Move the smaller circle so that it's completely outside the larger circle, but have the circles touch at exactly one point. This will allow for an internal common tangent plus two extra external common tangents.
- Pull the two circles completely apart. Make sure they don't touch at all. This will allow us to have four different common tangents. Two of those tangents are internal, while the others are external. An internal tangent cuts through the line that directly connects the centers of the circles.
Refer to the diagram below for examples of what I mean.