1 mole C3H8 produces 4 moles H2O. So, first we convert 32 grams of propane to moles and then find moles of H2O. Then convert moles of H2O to grams of H2O
Moles of H2O produced = 32 g C3H8 x 1 mole/44 g x 4 moles H2O/mole C3H8 = 2.909 moles H2O
Grams H2O produced = 2.909 moles H2O x 18 g/mole = 52.36 g = 52 g H2O
#b
According to Le C ha.te llors principle of we increase concentration of reactants or products equilibrium shifts.
#c
- Rate of reaction also increases
#e
Stated in b
13.8 moles of carbon = 12 g/mol*13.8 or 165.6 grams
165.6 grams/ 2.26 g/mL = 73.27434 or 73.3 mL
I hope this helps!!!!
Answer: B or C
Explanation: The question does not include the variable or steps Brian is using so either one could be correct. It has to be the one that he is controlling though. This is because a control group is used to rule out any alternate explanations. Therefore the answer should be the one that he is trying to test out.