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KatRina [158]
3 years ago
8

Explain how mixture melting points can be used to distinguish between two compounds

Chemistry
1 answer:
Over [174]3 years ago
5 0

generally melting point of mixture is always different from melting point of pure compound

lets say you have a two compounds called A and B

and you have a unknown compound called X which can be either A or B

now your target is to find unknown is really A or B right?

take some amount of X and mix it with A and B separately

out of these two mixtures one will be pure compound (because we initially assume that unknown can be either A or B)

suppose X + A is same melting with A then X is A

X +B will be less than the melting point of A or

suppose X+B is same melting point like B then X is B

X+A will be less than melting point of B

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Explain how boiling and evaporating are alike and how they are differant
julsineya [31]

Answer:

The main difference between evaporation and boiling are : 1. Evaporation takes place at all temperatures, while boiling occurs at a particular temperature. 2. Evaporation takes place from the surface, whereas the entire liquid boils. 3. Evaporation can occur using the internal energy of the system, while boiling requires an external source of heat.

7 0
4 years ago
What was used to build the phylogenetic
Gnom [1K]
A phylogenetic tree may be built using morphological (body shape), biochemical, behavioral, or molecular features of species or other groups. In building a tree, we organize species into nested groups based on shared derived traits (traits different from those of the group's ancestor).
8 0
3 years ago
If 12.5 grams of the original sample of cesium-137 remained after 90.6 years, what was the mass of the original sample?
myrzilka [38]

Answer:

Mass of original sample = 100 g

Explanation:

Half life of cesium-137 = 30.17 years

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac{\ln2}{t_{1/2}}

k=\frac{\ln2}{30.17}\ year^{-1}

The rate constant, k = 0.02297 year⁻¹

Time = 90.6 years

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Initial concentration [A_0] = ?

Final concentration [A_t] = 12.5 grams

Applying in the above equation, we get that:-

12.5\ g=[A_0]e^{-0.02297\times 90.6}

[A_0]=\frac{12.5}{e^{-0.02297\times 90.6}}\ g=100\ g

<u>Mass of original sample = 100 g</u>

8 0
3 years ago
Pressure is this sample?
faltersainse [42]

Answer:

P = 164 Atm

Explanation:

PV = nRT => P = nRT/V

n = 10.0 moles

R = 0.08206 L·Atm/mol·K

T = 27.0°C = 300 K

V = 1.50 Liters

P = (10.0 mol)(0.08206 L·Atm/mol·K )(300 K)/(1.50 Liters) = 164.12 Atm ≅ 164 Atm (3 sig. figs.)

5 0
3 years ago
Please help with these two (last question is nwse)
Vlad1618 [11]

Answer:

your answer gonna be 20 miles

5 0
3 years ago
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