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Fittoniya [83]
3 years ago
5

Substances have a fixed arrangement of atoms. true or false (NO LINKS PLEASE)

Chemistry
1 answer:
KATRIN_1 [288]3 years ago
5 0

Answer:

True

Explanation:

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Does the entropy (△S) increase or decrease in each of the following processes? The wind blows a pile of leaves all over the yard
garik1379 [7]
B, increasing decreasing is my opinion
6 0
4 years ago
For the skeletal chemical equation BF3(g) + NaH(s) → B2H6(g) + NaF(s) what is the coefficient of B2H6 in the balanced equation?
KonstantinChe [14]

Answer:

Coefficient in front of the B_2H_6  in the balanced equation - 1

Explanation:

The unbalanced Chemical equation is shown below as:-

BF_3+NaH\rightarrow B_2H_6+NaF

On the left hand side,  

There are 1 boron atom and 3 fluorine atoms and 1 sodium and hydrogen atoms.

On the right hand side,  

There are 2 boron atoms and 6 hydrogen atoms and 1 sodium and fluorine atoms.

Thus,  

leftside, BF_3 must be multiplied by 2 to balance boron and right side, NaF must be multiplied by 6 to balance fluorine. Left side, NaH must be multiplied by 6 to balance sodium and hydrogen atoms.

Thus, the balanced reaction is:-

2BF_3+6NaH\rightarrow B_2H_6+6NaF

<u>Coefficient in front of the B_2H_6  in the balanced equation - 1</u>

6 0
3 years ago
Read 2 more answers
Given:
bulgar [2K]

Answer:

The combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy

Explanation:

Given;

CH₄ + 2O₂ → CO₂ + 2H₂O, ΔH = -890 kJ/mol

From the combustion reaction above, it can be observed that;

1 mole of methane (CH₄) released 890 kilojoules of energy.

Now, we convert 59.7 grams of methane to moles

CH₄ = 12 + (1x4) = 16 g/mol

59.7 g of CH₄ = \frac{59.7}{16} = 3.73125 \ moles

1 mole of methane (CH₄) released 890 kilojoules of energy

3.73125 moles of methane (CH₄) will release ?

= 3.73125 moles x  -890 kJ/mol

= -3320.81 kJ

Therefore, the combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy

5 0
3 years ago
The pressure inside a compressed gas cylinder is 144 atm at 48°C. What will the pressure inside the cylinder be after it is cool
Andrews [41]
<h3>Answer:</h3>

134 atm

<h3>Explanation:</h3>
  • Based on the pressure law, the pressure of a gas varies directly proportionally to the absolute temperature at a constant volume.
  • Therefore; we are going to use the equation;

\frac{P1}{T1}=\frac{P2}{T2}

In this case;

Initial pressure, P1 = 144 atm

Initial temperature, T1 (48°C) = 321 K

Final temperature, T2 (25°C) = 298 K

We need to find the final pressure,

Therefore;

P2 = (P1/T1)T2

    = (144/321)× 298 K

    = 133.68 atm

   = 134 atm

Therefore, the new pressure will be 134 atm.

5 0
4 years ago
Calculate the volume of the gas, in liters, if 1.75 mol has a pressure of 1.28 atm at a temperature of -7 ∘C
Alexandra [31]

Answer:

A sample of an ideal gas has a volume of 2.21 L at 279 K and 1.01 atm. Calculate the pressure when the volume is 1.23 L and the temperature is 299 K.

 

You need to apply the ideal gas law PV=nRT

 

You have the pressure, P=1.01 atm

you have the volume, V = 2.21 L

The ideal gas constant R= 0.08205 L. atm/ mole.K at  273 K

 

find n = PV/RT = (1.01 atm x 2.21 L / 0.08205 L.atm/ mole.K x 273 K)

 

n= 0.1 mole, Now find the pressure for n=0.1 mole, T= 299K and

L=1.23 L

 

P=nRT/V= 0.1mole x 0.08205 (L.atm/ mole.K x 299 k)/ 1.23 L

= 1.994 atm

Explanation:

6 0
3 years ago
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