Answer:
(a)
Average velocity = < 0, 316000, 146000> m/s
(b) < 0, 2.844, 1.314 > m
Explanation:
r1 = < 0.02, 0.04, - 0.06 > m
r2 = < 0.02, 1.62, - 0.79 > m
time, t = 5 micro second = 5 x 10^-6 s
(a) Average velocity is defined as the ratio of total displacement to the total time taken.
Displacement = r = r2 - r1
r = < 0.02 - 0.02, 1.62 - 0.04, - 0.79 + 0.06 > m
r = < 0, 1.58, - 0.73 > m
So. Average velocity = ![\frac{< 0, 1.58, - 0.73 >}{5 \times 10^{-6}}](https://tex.z-dn.net/?f=%5Cfrac%7B%3C%200%2C%201.58%2C%20-%200.73%20%3E%7D%7B5%20%5Ctimes%2010%5E%7B-6%7D%7D)
Average velocity = ![< 0, 316000, 146000> m/s](https://tex.z-dn.net/?f=%3C%200%2C%20316000%2C%20146000%3E%20m%2Fs)
Average velocity = < 0, 316000, 146000> m/s
(b)
Distance = velocity x time
Here time, t = 9 micro second
d = < 0, 316000, 146000> x 9 x 10^-6 m
d = < 0, 2.844, 1.314 > m