Answer:
Induced emf is 0.324 V
Explanation:
We have,
Number of turns, n = 61.6
Radius of circular coil, r = 4.44 cm
Resistance of coil, R = 2.34 Ω
The magnitude of the magnetic field varies in time according to the expression :


The magnitude of the induced emf in the coil is given by :


At t = 9.21 s,



So, the magnitude of the induced emf in the coil is 0.324 V
Answer:
The magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 1.01 x
N/C
Explanation:
given information,
kinetic energy, KE = 3.25 x
J
proton's mass, m = 1.673 x
kg
charge, q = 1.602 x
C
distance, d = 2 m
to find the electric field that will stop the proton, we can use the following equation:
E = F/q
= (KE/d) / q , KE = Fd --> F = KE/d
= KE/qd
= (3.25 x
J) / (1.602 x
C)(2 m)
= 1.01 x
N/C
The motorist is traveling at 65 miles per hour
The statement "<span>The motion of a pendulum for which the maximum displacement from equilibrium does not change is an example of simple harmonic motion." is true.
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