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3 years ago

Explain why urban sprawl occurs even though it negatively impacts the environment.

Physics

2 answers:

V125BC [204]3 years ago

6 0

Answer:

Step-by-Step Explanation:

The urban sprawl is basically started due to the development of our country.

Country is stepping ahead from developing country to developed country.

It negatively impacts the environment because excessively we are cutting trees.

Excess of everything is bad.

If we are cutting 1 tree we should grow 2 trees in behalf of that 1 tree.

Development is also necessary and for those who have shifted form rural to urban areas.Facilities have to be provided.So, shopping malls, industries are getting constructed.

Grace [21]3 years ago

3 0

Urban sprawl occurs when housing is filled in one location and car dependent communities are forced to moved away from the central urban areas where the population is too vast, even though this impacts the environment by increasing pollution and causing environmental degradation.

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Do sound waves must have a medium to travel but elctromagnetic waves cannot

ra1l [238]

No don't feel feel like they do

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3 years ago

During a test, a NATO surveillance radar system, operating at 37 GHz at 182 kW of power, attempts to detect an incoming stealth

Marta_Voda [28]

(a) $2.68\cdot 10^{-6} W/m^2$

The intensity of an electromagnetic wave is given by

$I=\frac{P}{A}$

where

P is the power

A is the area of the surface considered

For the waves in the problem,

$P=182 kW = 1.82\cdot 10^5 W$ is the power

The area is a hemisphere of radius

$r=104 km=1.04\cdot 10^5 m$

$A=2\pi r^2=2\pi (1.04\cdot 10^5 m)^2=6.8\cdot 10^{10} m^2$

So, the intensity is

$I=\frac{1.82\cdot 10^5 W}{6.8\cdot 10^{10}m^2}=2.68\cdot 10^{-6} W/m^2$

(b) $5.9\cdot 10^{-7} W$

In this case, the area of the reflection is

$A=0.22 m^2$

So, if we use the intensity of the wave that we found previously, we can calculate the power of the aircraft's reflection using the same formula:

$P=IA=(2.68\cdot 10^{-6} W/m^2)(0.22 m^2)=5.9\cdot 10^{-7} W$

(c) $8.7\cdot 10^{-18} W/m^2$

We said that the power of the waves reflected by the aircraft is

$P=5.9\cdot 10^{-7} W$

If we assume that the reflected waves also propagate over a hemisphere of radius

$r=104 km=1.04\cdot 10^5 m$

which has an area of

$A=2\pi r^2=2\pi (1.04\cdot 10^5 m)^2=6.8\cdot 10^{10} m^2$

Then the intensity of the reflected waves at the radar site will be

$I=\frac{P}{A}=\frac{5.9\cdot 10^{-7} W}{6.8\cdot 10^{10} m^2}=8.7\cdot 10^{-18} W/m^2$

(d) $8.1\cdot 10^{-8} V/m$

The intensity of a wave is related to the maximum value of the electric field by

$I=\frac{1}{2}c\epsilon_0 E_0^2$

where

c is the speed of light

$\epsilon_0$ is the vacuum permittivity

$E_0$ is the maximum value of the electric field vector

Solving the equation for $E_0$ ,

$E_0=\sqrt{\frac{2I}{c\epsilon_0}}=\sqrt{\frac{2(8.7\cdot 10^{-18} W/m^2)}{(3\cdot 10^8 m/s)(8.85\cdot 10^{-12} F/m)}}=8.1\cdot 10^{-8} V/m$

(e) $1.9\cdot 10^{-16} T$

The maximum value of the magnetic field vector is given by

$B_0 = \frac{E_0}{c}$

Substituting the values,

$B_0 = \frac{(8.1\cdot 10^{-8} V/m)}{3\cdot 10^8 m/s}=2.7\cdot 10^{-16} T$

And the rms value of the magnetic field is given by

$B_{rms} = \frac{B_0}{\sqrt{2}}=\frac{2.7\cdot 10^{-16} T}{\sqrt{2}}=1.9\cdot 10^{-16} T$

7 0

3 years ago

How to rearrange the formula f = ma and solve for m

GuDViN [60]

F /a = m

is the answer

7 0

3 years ago

Read 2 more answers

Acceleration is a change in?

konstantin123 [22]

Acceleration is any change in speed or direction of motion.

Speed and direction together comprise 'velocity'.

3 0

3 years ago

Read 2 more answers

A tiny particle with charge + 5.0 μC is initially moving at 55 m/s. It is then accelerated through a potential difference of 500

Vadim26 [7]

Answer:

ΔK.E = 2.5 × 10⁻³ J

Explanation:

Given data in the question, we have:

Charge of the particle, q = 5.0 μC = 5 × 10 ⁻⁶ C

Initial speed of the particle, v = 55 m/s

The potential difference, ΔV = 500 V

Now, the gain in kinetic energy is given as

ΔK.E = q × ΔV

on substituting the values in the above formula, we get

ΔK.E = 5 × 10 ⁻⁶ C × 500 V

ΔK.E = 2.5 × 10⁻³ J

8 0

3 years ago