10 joules of work is done by the object
Energy Density = 1/2 × ε(0) × (V/d)^2
V = 100, d = 0.01, ε(0) = 8.85 x 10^-12
Answer:
50 W
Explanation:
Case 1
Power = V * I
100 = 220 * I
I =
A
Case 2
P = V * I
P = 110 * 
P = 50 W
I think the answer is 50 W
Hope it helps
A. very small objects behave like like particles.
Answer:
The minimum wall thickness required for the spherical tank is 0.0189 m
Explanation:
Given data:
d = inside diameter = 8.1 m
P = internal pressure = 1.26 MPa
σ = 270 MPa
factor of safety = 2
Question: Determine the minimum wall thickness required for the spherical tank, tmin = ?
The allow factor of safety:

The minimun wall thickness:
