Air resistance is ignored.
g = 9.8 m/s².
At maximum height, the vertical velocity is zero.
Let h = the maximum height reached.
Let u = the vertical launch velocity.
Because ot takes 5.0 seconds to reach maximum height, therefore
(u m/s) - (9.8 m/s²)*(5 s) = 0
u = 49 m/s
The maximum height reached is
h = (49 m/s)*(5 s) - (1/2)*(9.8 m/s²)*(5 s)²
= 122.5 m
Answer: 122.5 m
Answer:
20.The first factor is the amount of charge on each object. The greater the charge, the greater the electric force. The second factor is the distance between the charges. The closer together the charges are, the greater the electric force is
Explanation:
Answer: I think the answer C
Explanation:
Answer:
-36.4 m/s
Explanation:
final velocity= initial velocity + acceleration x time
7 + (-9.8)(3)= -36.4 m/s
<h2>
Answer:442758.96N</h2>
Explanation:
This problem is solved using Bernoulli's equation.
Let be the pressure at a point.
Let be the density fluid at a point.
Let be the velocity of fluid at a point.
Bernoulli's equation states that for all points.
Lets apply the equation of a point just above the wing and to point just below the wing.
Let be the pressure of a point just above the wing.
Let be the pressure of a point just below the wing.
Since the aeroplane wing is flat,the heights of both the points are same.
So,
Force is given by the product of pressure difference and area.
Given that area is .
So,lifting force is