Static friction keeps the car from skidding off the road and points toward the center of the curve. By Newton's second law, the car experiences
• net vertical force
F [normal] - F [weight] = 0
• net horizontal force
F [friction] = ma = mv²/r
where v is the tangential speed of the car.
It follows that
F [normal] = F [weight] = mg
and when static friction is maximized at the car's maximum speed,
F [friction] = µ F[normal] = 0.402 mg
Solve for v :
0.402 mg = mv²/r ⇒ v = √(0.402 g (93.5 m)) ≈ 19.2 m/s
Answer:
I = 0.287 MR²
Explanation:
given,
height of the object = 3.5 m
initial velocity = 0 m/s
final velocity = 7.3 m/s
moment of inertia = ?
Using total conservation of mechanical energy
change in potential energy will be equal to change in KE (rotational) and KE(transnational)
PE = KE(transnational) + KE (rotational)
v = r ω
I = 0.287 MR²
The formula for the voltage is shown below:
Voltage = Current x Resistance
V=I x R
When we change voltage:
I =V/R or R=V/I
Increasing the voltage in an electrical circuit will also increase the current value, as well as the resistance of the load,
Answer:
Gravitational potential energy is due to the position of an object above Earth's surface. The object has the potential to fall due to gravity.
Explanation:
Gravitational potential energy depends on an object's weight and its height above the ground (GPE = weight x height). hope this helps you :)
Answer:
2.5 ms^-2
Explanation:
acceleration
= (final velocity - initial velocity)/time
= [(40m/s) - (20m/s)]/8s
= (20m/s)/8s
= 5/2 m/s²
= 2.5 m/s²
= 2.5 ms^-2
