Answer:
d = 142.5 m
Explanation:
This is a vector exercise. Let's calculate how much the boat travels in the 40s
d₀ = 
t
d₀ = 0.75 40
d₀ = 30 m
Let's write the kinematic equations
Boat
x = d₀ + t
x = 0 + 
t
At the meeting point the coordinate is the same for both
d₀ + t = t
t ( - ) = d₀
t = d₀ / ( - )
The two go in the same direction therefore the speeds have the same sign
t = 30 / (0.95-0.775)
t = 150 s
The distance traveled by man is
d = t
d = 0.95 150
d = 142.5 m
If the boy outputs enough weight upon the ball in response the ball will move.
Please vote my answer brainliest! Thanks.
(a) The acceleration of the salt shaker is 1.18 m/s².
(b) The distance traveled by the baseball player before coming to rest is 204.1 m.
<h3>
Acceleration of the salt shaker</h3>
The acceleration of the salt shaker at the given coefficient of kinetic friction is determined as follows;
a = μg
a = 0.12 x 9.8
a = 1.18 m/s²
Acceleration of the baseball player is calculated as follows;
a = μg
a = 0.4 x 9.8
a = 3.92 m/s²
<h3>Distance traveled by the baseball player</h3>
The distance traveled by the baseball player before coming to rest is calculated as follows;
v² = u² - 2as
0 = 40² - 2(3.92)s
0 = 1600 - 7.84s
7.84s = 1600
s = 204.1 m
The complete question is below:
A baseball player slides into third base with an initial speed of 40 m/s. If the coefficient of kinetic friction between the player and the ground is 0.40, how far does the player slide before coming to rest?
Learn more about coefficient of friction here: brainly.com/question/20241845
Energy (E) = Planck's constant (h) * frequency (nu)
therefore, frequency ~
I believe the answer is node, but I'm not totally sure.
