Answer:
A. Final pressure P2
P2/P1 = (T2/T1)^n/n-1
P1 = 4bar
T1 = 438K
T2 = 300K
Polytropic index, n, = 1.3
P2 = 4 (300/438)^1.3/1.3-1
P2 = 4 (300/438)^4.333
P2 = 4 * 0.19400
P2 = 0.776bar.
B. The work done is;
W = mR/ n-1 (T1 -T2)
Where, R = 0.1889kJ/kg.K, m = 1
W = 1 * 0.1889/ 1.3-1 * (438-300)
W = 86.89kJ/kg.
C. The heat transfer, Q
Q = W + ΔU
Q = W + mCv(T2-T1), where Cv of nitrogen is 0.743kj/kgk
Q = 86.89 + 1 * 0.743 (300-438)
Q = 86.89 + (-102.534)
Q = -15.644kJ/K
Q = 15.64kJ/K
Answer:
Explanation:
λ(x) = λo x/ L
(a) The total charge is Q.




λo = 2Q/L
(b)
Let at a distance x from the origin the charge is dq.
so, dq = (2Q/L) x/ L dx

The potential due to this small charge at a distance d to the left of origin






Answer:
the answer is C
Explanation:
i took the test just now so i am glad i can help someone in the future❣❣❣❣
<u><em>Also here is the explanation</em></u>
Note that the magnitude of acceleration (a) is given by a =
v2
R
, where v is the speed and R is the radius. Because acceleration is the same for both bikers, the ratio 
v2
R
, also has to be the same for both. Given that Kevin’s speed is higher, the radius of his path must also be higher to maintain the same ratio. Therefore, Kevin’s circular path has a bigger radius than Linda’s path.
The universe will collapse