Answer:
h =220 m
Explanation:
Given that
u = 7 m/s
Even mass will attach but this will not produce any effect on the maximum height of the ball.Because in energy conservation the effect of mass does not present.
So the final speed of the ball will be zero at the maximum height.
v² = u² - 2 g (25 + h)
0 = 7² - 2 x 10 (25 +h)
49 = 20 ( 25 +h)
49 = 500 +20 h
Here h comes out negative that is why we are taking the 70 m/s in place of 7 m/s.
0 = 70² - 2 x 10 (25 +h) ( take g =10 m/s²)
4900 = 20 ( 25 +h)
4900 = 500 +20 h
4900- 500 = 20 h
4400 = 20 h
440 = 2 h
h =220 m
Answer:
81 J.
Explanation:
From the question given above, the following data were obtained:
Specific heat capacity (C) = 0.45 J/gK.
Temperature change (ΔT) = 15 K
Mass = 12 g
Heat required (Q) =?
The heat required to raise the temperature of iron can be obtained as illustrated below:
Q = MCΔT
Q = 12 × 0.45 × 15
Q = 81 J
Therefore, the heat required to raise the temperature of the iron is 81 J.
ANS : 313℃
You need to use K in this.
To convert ℃ to Kelvin (K), add 273.15 to ℃.
Assuming that the can is motionless, we can then assume that the vertical component of T = mg and that Fe = the horizontal component of T.
<span> Since T itself is larger than it's vertical or horizontal components separately, then T is greater than all the forces.</span>
